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                            340                 Approximation of Probability Distributions

                            then
                                   Pr(|X n − X|≥ 1/2) = Pr(X n = 1 ∩ X = 0) + Pr(X n = 0 ∩ X = 1)
                                                       1 n + 1  1 n − 1
                                                    =        +
                                                       4  n    4   n
                                                       1
                                                    =   ;
                                                       2
                            it follows that X n does not converge to X in probability.
                              On the other hand, suppose that
                                                                                    1
                                         Pr(X n = 1|X = 1) = 1  and  Pr(X n = 1|X = 0) =  .
                                                                                    n
                            Note that
                                 Pr(X n = 1) = Pr(X n = 1|X = 1)Pr(X = 1) + Pr(X n = 1|X = 0)Pr(X = 0)
                                             1   1 1
                                           =   +
                                             2   n 2
                                             1 n + 1
                                           =        ,
                                             2   n
                            as stated above. In this case, for any  > 0,
                                                                                            1
                                  Pr(|X n − X|≥  ) = Pr(X n = 1 ∩ X = 0) + Pr(X n = 0 ∩ X = 1) =
                                                                                           2n
                                     p
                            so that X n → X as n →∞.

                              The preceding example shows that convergence in distribution does not necessarily imply
                            convergence in probability. The following result shows that convergence in probability does
                            imply convergence in distribution. Furthermore, when the limiting random variable is a
                            constant with probability 1, then convergence in probability is equivalent to convergence in
                            distribution.


                            Corollary 11.3. Let X, X 1 , X 2 ,... denote real-valued random variables.
                                       p                    D
                               (i) If X n → Xas n →∞ then X n → Xas n →∞.
                                       D                                                      p
                              (ii) If X n → Xas n →∞ and Pr(X = c) = 1 for some constant c, then X n → Xas
                                  n →∞.

                                                  p
                            Proof. Suppose that X n → X. Consider the event X n ≤ x for some real-valued x.If
                            X n ≤ x, then, for every  > 0, either X ≤ x +   or |X n − X| > . Hence,
                                           Pr(X n ≤ x) ≤ Pr(X ≤ x +  ) + Pr(|X n − X| > ).
                            Let F n denote the distribution function of X n and let F denote the distribution function of
                            F. Then, for all  > 0,
                                                     lim sup F n (x) ≤ F(x +  ).
                                                      n→∞
                              Similarly, if, for some  > 0, X ≤ x −  , then either X n ≤ x or |X n − X| > . Hence,
                                                F(x −  ) ≤ F n (x) + Pr(|X n − X| > )
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