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1 92                                  Isothermal Reactor Design   Chap. 4

                              The initial volume of fluid in a vat is to be 5  dm3 with a bromine cyanide concen-
                              tration of  0.05 mol/dm3. The specific reaction rate constant is
                                                      k  = 2.2 dm3/s. mol
                              Solve for the concentrations of  bromine cyanide and methyl bromide and the rate of
                              reaction as a function of time.

                              Solution
                              Symbolically, we write the reaction as   \
                                                        A+B+C+D
                              The reaction is elementary; therefore, the rate law is
                                                       (-TA=kCACBJ
                  Rate Law                                                            (E4-11.1)

                              Substituting the rate law in Equations (4-56) and (4-58) gives

             Mole balances on                                                         (E4-11.2)
              A, B, C, and D






                                                       p-?                            (E4- i .a;!
                                                        v = Vo+v,t
                                                                                         1
                           I  Similarly for C and D we have

                                                                                      (E4- 1 1.5)






                             Then
           Polymath will com-                        dCc = kCACB - y                  (E4- 1 1.7)
           bine for you. Thank
              you Polymath!

                             and

                                                                                     (E4- 1 1.8)


                           1  We could also calculate the conversion of A.

                                                       x=- NAO  - NA                 (E4-11.9)
                                                             "40
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