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Sec. 7.4   Enzymatic Reaction Fundamentals                     39 1
















                                                                  -
                                                     0
                                                                  so-  s
                                                                     t

                                                    Figure 7-12  Evaluating V,,  and K,.

                                   Exczmple 7-8  Batch Enzymatic Reactors

                                   Calculate the time needed to convert 80% of the urea to ammonia and carbon diox-
                                   ide in a 0.5-dm3 batch reactor. The initial concentration of urea is 0.1 mol/dm3, and
                                   the urease concentration is 0.001 g/dm3. The reaction is to be carried out isother-
                                   mally at the same temperature at which the data in Table E7-7.1 were obtaine:d.
                                   Solution
                                   We can use Equation (7-95),

                                                                                              r:  7-95)

                                   whiere K,  = 0.0266 g mol/dm3, X  = 0.8, and CuEaO = 0.1 g mol/dm3, V,,,  was
                                   1.33 g  mol/dm3.s.  However, for  the conditions in  the  batch reactor, the  enzyme
                                   Concentration is  only  0.001 g/dm3. Because  V,,   = E,.k3,  V,,,   for  the  second
                                   enz,yme concentration is

                                            vm,z  = - v,,,   = -                  mol/s.dm3
                                                  E* 2
                                                            o'ool  X  1.33 = 2.66 X
                                                  Et 1        5
                                 I
                                                        X  = 0.8
                                                         t= -
                                                                      1
                                                             0.0266
                                                                          (0.8)(0.1)
                                                                    ln-+
                                                            0.000266  0.2  0.000266
                                                          = 160.9 -t 300.8
                                                          = 461.7 s
                                      7.4.4  Inhibition of  Enzyme Reactions

                                      Another factor that greatly influences the rates of enzyme-catalyzed reac-
                                 tions in addition to pH is the presence of an inhibitor. The most dramatic con-
                                 sequences  of  enzyme  inhibition  are  found  in  living  organisms,  when:  the
                                                               I
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