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Sec. 8.2   The Energy Balance                                  437
                                  Example 8-3  Heat of Reaction

                                  Calculate the  heat  of  reaction for  the  synthesis of  ammonia  from hydrogen  and
                                  nitrogen at  150°C in kcal/mol of  N2 reacted and in kJ/mol of  H2 reacted.
                                  Solzition

                                                                       2NH3
                                                         N2 + 3H2  4
                                  Calculate the heat of reaction at the reference temperature using the heats of forma-
                                                                                 3
                                  tion  of  the reactiug species obtained from Perry's  Handbook or the Handbook of
                                  Chemistry and Physics.
                                                        = 2H~3(TR)-3H;;2(TR)-H~2(TR)        (~a,-3.i)

                                  The heats of formation of  the elements (H,,  N2) are zero at 25°C.
                                                 AH;Z,(TR)  = 2H&$TR)-3(0)-0   2Hk3
                                                         = 2(-11,020) -
                                                                      Cal
                                                                     mol N,
                                                         = -22,040 cal/mol N,  reacted
                                  or
                                                 AHix(298 K) = -22.04 kcal/mol N,  reacted
                                                            = -92.22 W/mol N,  reacted
                Exothermic reaction   The minus sign indicates the reaction is exothemzic. If  the heat capacities are con-
                                  stant or if the mean heat capacities over the range 25 to 150°C are readily available,
                                  the determination of aHRx at  150°C is quite simple.

                                                  CPHZ = 6.992 cal/mol H,. K
                                                  CPN2 = 6.984 cal/mol N,  K

                                                        8.92
                                                 tpNH, cal/mol NH,  K
                                                      =
                                                  ACp = 2CpNH - 3CpH2 - CPN2                (E8-3.2)
                                                      = 2(8.92) - 3(6.992) - 6.984
                                                      = - 10.12 cal/g mol N, reacted-K

                                              AHR,(T)  = AH~x(~R)+A~,(~-~R)                   (8.-27)
                                           AH~,(423 K) = -22,040+  (-10.12)(423-298)
                                                      = -23,310 cal/mol N,  = -23.31 kcallmol N,
                                                      = -97,530 J/mol N,
                                                                               (Recall:  1 cal = 4.18.4 J)

                                 R.  H.  Perry,  D. 'W.  Green, and  J.  0. Maloney,  eds., Perry's  Chemical  Engine,ers'
                                 Handbook, 6th ed. (New York: McGraw-Hill,  1984), pp. 3-147.
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