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PROBLEMS                                                              73


                 2.2 Convert the following binary numbers to decimal by using the method of positional
                      weights:
                      (a) 0110
                      (b) 1011
                      (c) 11001
                      (d) 11011001.11
                      (e) 0.01011

                 2.3 Convert the decimal numbers of Problem 2.1 to BCD.
                 2.4 Convert the binary numbers of Problem 2.2 to BCD. To do this, add trailing and
                      leading O's as required.
                 2.5 Convert the following BCD numbers to binary:
                      (a) 00010011
                      (b) 01010111
                      (c) 0101000110
                      (d) 1001000.00100101
                      (e) 0.100001110101

                 2.6 Convert the decimal numbers in Problem 2.1 to XS3.
                 2.7 Convert the BCD numbers in Problem 2.5 to XS3.
                 2.8 Convert the binary numbers in Problem 2.2 to BCH.

                 2.9 Convert the BCD numbers in Problem 2.5 to BCD.
                 2.10 Convert the following numbers to binary:
                      (a) 613520 8
                      (b) 2FD6A25B, 6
                      (c) 11110011100.011xs3
                      (d) 6!
                 2.11 Convert the following fractions as indicated:
                      (a) 0.534io -» N 2 rounded to 8 bits.
                     (b) 0.3DF2 [6 -> 7V 2 rounded to 8 bits.
                      (c) 0.534io —> N\(, terminated at 4 digits.
                     (d) 0.5427 8 -> N 2 rounded to 8 bits.
                 2.12 Convert the following numbers to signed-magnitude binary form:
                      (a) +56.25,0
                      (b) -94.625,0
                      (c) -7m5, 6
                     (d) +125 8
                      (e) -0110101.1001 IBCD
                 2.13 Give the radix complement representation for the following numbers:
                      (a) The 10's complement of 47.63,o
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