Page 119 - Engineering Electromagnetics, 8th Edition
P. 119
CHAPTER 4 Energy and Potential 101
Wemaystartbyvisualizinganemptyuniverse.Bringingacharge Q 1 frominfinity
2
to any position requires no work, for there is no field present. The positioning of
Q 2 at a point in the field of Q 1 requires an amount of work given by the product of
the charge Q 2 and the potential at that point due to Q 1 .We represent this potential
as V 2,1 , where the first subscript indicates the location and the second subscript the
source. That is, V 2,1 is the potential at the location of Q 2 due to Q 1 . Then
Work to position Q 2 = Q 2 V 2,1
Similarly, we may express the work required to position each additional charge
in the field of all those already present:
Work to position Q 3 = Q 3 V 3,1 + Q 3 V 3,2
Work to position Q 4 = Q 4 V 4,1 + Q 4 V 4,2 + Q 4 V 4,3
and so forth. The total work is obtained by adding each contribution:
Total positioning work = potential energy of field
= W E = Q 2 V 2,1 + Q 3 V 3,1 + Q 3 V 3,2 + Q 4 V 4,1
(39)
+Q 4 V 4,2 + Q 4 V 4,3 +· · ·
Noting the form of a representative term in the preceding equation,
Q 1 Q 3
Q 3 V 3,1 = Q 3 = Q 1
4π 0 R 13 4π 0 R 31
where R 13 and R 31 each represent the scalar distance between Q 1 and Q 3 ,we see that
it might equally well have been written as Q 1 V 1,3 .If each term of the total energy
expression is replaced by its equal, we have
(40)
W E = Q 1 V 1,2 + Q 1 V 1,3 + Q 2 V 2,3 + Q 1 V 1,4 + Q 2 V 2,4 + Q 3 V 3,4 + ···
Adding the two energy expressions (39) and (40) gives us a chance to simplify the
result a little:
2W E = Q 1 (V 1,2 + V 1,3 + V 1,4 + ···)
+ Q 2 (V 2,1 + V 2,3 + V 2,4 +· · ·)
+ Q 3 (V 3,1 + V 3,2 + V 3,4 +· · ·)
+· · ·
Each sum of potentials in parentheses is the combined potential due to all the charges
except for the charge at the point where this combined potential is being found. In
other words,
V 1,2 + V 1,3 + V 1,4 +· · · = V 1
2 However, somebody in the workshop at infinity had to do an infinite amount of work to create the
point charge in the first place! How much energy is required to bring two half-charges into coincidence
to make a unit charge?