Page 210 - Engineering Electromagnetics, 8th Edition
P. 210

192                ENGINEERING ELECTROMAGNETICS
















                                                 Figure 7.9 The magnetic field intensity as a function of
                                                 radius in an infinitely long coaxial transmission line with
                                                 the dimensions shown.



                                        The external field is zero. This, we see, results from equal positive and negative
                                     currents enclosed by the path. Each produces an external field of magnitude I/2πρ,
                                     but complete cancellation occurs. This is another example of “shielding”; such a
                                     coaxial cable carrying large currents would, in principle, not produce any noticeable
                                     effect in an adjacent circuit.
                                        As a final example, let us consider a sheet of current flowing in the positive y
                                     direction and located in the z = 0 plane. We may think of the return current as equally
                                     divided between two distant sheets on either side of the sheet we are considering. A
                                     sheet of uniform surface current density K = K y a y is shown in Figure 7.10. H cannot
                                     vary with x or y.If the sheet is subdivided into a number of filaments, it is evident
                                     that no filament can produce an H y component. Moreover, the Biot-Savart law shows
                                     that the contributions to H z produced by a symmetrically located pair of filaments
                                     cancel. Thus, H z is zero also; only an H x component is present. We therefore choose
                                     the path 1-1 -2 -2-1 composed of straight-line segments that are either parallel or



















                                                 Figure 7.10 A uniform sheet of surface current
                                                 K = K y a y in the z = 0 plane. H may be found by applying
                                                 Amp ` ere’s circuital law about the paths 1-1 -2 -2-1 and



                                                 3-3 -2 -2-3.
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