Page 227 - Engineering Electromagnetics, 8th Edition
P. 227

CHAPTER 7   The Steady Magnetic Field         209

                     equations that apply to static electric fields and steady magnetic fields is


                                            D · dS = Q =    ρ ν dν
                                           S             vol

                                            E · dL = 0
                                                                                     (41)

                                            H · dL = I =  J · dS
                                                         S

                                            B · dS = 0
                                           S
                         Our study of electric and magnetic fields would have been much simpler if we
                     could have begun with either set of equations, (37) or (41). With a good knowledge
                     of vector analysis, such as we should now have, either set may be readily obtained
                     from the other by applying the divergence theorem or Stokes’ theorem. The various
                     experimental laws can be obtained easily from these equations.
                         As an example of the use of flux and flux density in magnetic fields, let us find
                     the flux between the conductors of the coaxial line of Figure 7.8a. The magnetic field
                     intensity was found to be
                                                   I
                                            H φ =      (a <ρ < b)
                                                 2πρ
                     and therefore
                                                         µ 0 I
                                              B = µ 0 H =    a φ
                                                         2πρ
                         The magnetic flux contained between the conductors in a length d is the flux
                     crossing any radial plane extending from ρ = a to ρ = b and from, say, z = 0to
                     z = d
                                                      d
                                                         b  µ 0 I
                                      
 =   B · dS =         a φ · dρ dz a φ
                                           S         0  a 2πρ
                     or
                                                     µ 0 Id  b
                                                
 =      ln                          (42)
                                                      2π   a
                         This expression will be used later to obtain the inductance of the coaxial trans-
                     mission line.


                        D7.7. A solid conductor of circular cross section is made of a homogeneous
                        nonmagnetic material. If the radius a = 1 mm, the conductor axis lies on the
                        z axis,andthetotalcurrentinthea z directionis20A,find:(a) H φ atρ = 0.5mm;
                        (b) B φ at ρ = 0.8 mm; (c) the total magnetic flux per unit length inside the
                        conductor; (d) the total flux for ρ< 0.5 mm; (e) the total magnetic flux outside
                        the conductor.

                        Ans. 1592 A/m; 3.2 mT; 2 µWb/m; 0.5 µWb; ∞
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