Page 252 - Engineering Electromagnetics, 8th Edition
P. 252

234                ENGINEERING ELECTROMAGNETICS

                                     and thus the Lorentz force equation may be applied to surface current density,

                                                                dF = K × B dS                         (6)

                                     or to a differential current filament,

                                                                dF = IdL × B                          (7)

                                        Integrating (5), (6), or (7) over a volume, a surface which may be either open or
                                     closed (why?), or a closed path, respectively, leads to the integral formulations

                                                               F =    J × B dν                        (8)
                                                                    vol

                                                                     K × B dS                         (9)
                                                               F =
                                                                    S
                                     and

                                                        F =    IdL × B =−I    B × dL                 (10)

                                        One simple result is obtained by applying (7) or (10) to a straight conductor in a
                                     uniform magnetic field,

                                                                 F = IL × B                          (11)

                                     The magnitude of the force is given by the familiar equation

                                                                 F = BIL sin θ                       (12)
                                     where θ is the angle between the vectors representing the direction of the current flow
                                     and the direction of the magnetic flux density. Equation (11) or (12) applies only to
                                     a portion of the closed circuit, and the remainder of the circuit must be considered in
                                     any practical problem.


                   EXAMPLE 8.1
                                     As a numerical example of these equations, consider Figure 8.2. We have a square
                                     loop of wire in the z = 0 plane carrying 2 mA in the field of an infinite filament on
                                     the y axis, as shown. We desire the total force on the loop.
                                     Solution. The field produced in the plane of the loop by the straight filament is
                                                                 I       15
                                                            H =    a z =   a z A/m
                                                                2πx     2πx
                                     Therefore,
                                                                             3 × 10 −6
                                                                      −7
                                                     B = µ 0 H = 4π × 10 H =        a z T
                                                                                x
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