Page 323 - Engineering Electromagnetics, 8th Edition
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CHAPTER 10   Transmission Lines           305

                                                    KCL                    +



                                                 g
                                                           c
                                                                               +

                                                                   KVL

                          Figure 10.3 Lumped-element model of a short transmission line section
                          with losses. The length of the section is  z. Analysis involves applying
                          Kirchoff’s voltage and current laws (KVL and KCL) to the indicated loop
                          and node, respectively.

                         First, KVL is applied to the loop that encompasses the entire section length, as
                     shown in Figure 10.3:
                                      1        1 ∂ I      1    ∂ I  ∂ I
                                  V =   RI z +   L   z +   L     +        z
                                      2        2  ∂t      2   ∂t    ∂t
                                        1
                                      +   R(I +  I) z + (V +  V )                     (1)
                                        2
                         We can solve Eq. (1) for the ratio,  V/ z, obtaining:
                                     V  =− RI + L   ∂ I  1 ∂ I    1  R I              (2)

                                                          L
                                      z             ∂t  +  2  ∂t  +  2
                     Next, we write:
                                            ∂ I                   ∂V
                                       I =     z     and    V =      z                (3)
                                            ∂z                    ∂z
                     which are then substituted into (2) to result in
                                       ∂V           z ∂           ∂ I
                                           =− 1 +           RI + L                    (4)
                                        ∂z          2 ∂z          ∂t
                     Now, in the limit as  z approaches zero (or a value small enough to be negligible),
                     (4) simplifies to the final form:

                                             ∂V  =− RI + L  ∂ I                       (5)

                                              ∂z            ∂t
                         Equation (5) is the first of the two equations that we are looking for. To find the
                     second equation, we apply KCL to the upper central node in the circuit of Figure 10.3,
                     noting from the symmetry that the voltage at the node will be V +  V/2:
                                                                     V

                                    I = I g + I c + (I +  I) = G z V +
                                                                     2

                                              ∂        V
                                        + C z     V +      + (I +  I)                 (6)
                                              ∂t       2
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