Page 36 - Engineering Electromagnetics, 8th Edition
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18                 ENGINEERING ELECTROMAGNETICS


                   EXAMPLE 1.3
                                     Transform the vector B = ya x − xa y + za z into cylindrical coordinates.

                                     Solution. The new components are
                                               B ρ = B · a ρ = y(a x · a ρ ) − x(a y · a ρ )
                                                  = y cos φ − x sin φ = ρ sin φ cos φ − ρ cos φ sin φ = 0
                                               B φ = B · a φ = y(a x · a φ ) − x(a y · a φ )
                                                                                    2
                                                                           2
                                                  =−y sin φ − x cos φ =−ρ sin φ − ρ cos φ =−ρ
                                     Thus,

                                                               B =−ρa φ + za z


                                        D1.5. (a)Give the rectangular coordinates of the point C(ρ = 4.4,φ =
                                             ◦
                                        −115 , z = 2). (b)Give the cylindrical coordinates of the point D(x =
                                        −3.1, y = 2.6, z =−3). (c) Specify the distance from C to D.
                                        Ans. C(x =−1.860, y =−3.99, z = 2); D(ρ = 4.05,φ = 140.0 , z =−3); 8.36
                                                                                         ◦

                                        D1.6. Transform to cylindrical coordinates: (a) F = 10a x −8a y +6a z at point
                                        P(10, −8, 6); (b) G = (2x + y)a x −(y −4x)a y at point Q(ρ, φ, z). (c)Give the
                                        rectangular components of the vector H = 20a ρ − 10a φ + 3a z at P(x = 5,
                                        y = 2, z =−1).

                                                              2      2                       2      2
                                        Ans. 12.81a ρ +6a z ;(2ρ cos φ −ρ sin φ +5ρ sin φ cos φ)a ρ +(4ρ cos φ −ρ sin φ
                                        − 3ρ sin φ cos φ)a φ ; H x = 22.3, H y =−1.857, H z = 3



                                     1.9 THE SPHERICAL COORDINATE SYSTEM
                                     We have no two-dimensional coordinate system to help us understand the three-
                                     dimensional spherical coordinate system, as we have for the circular cylindrical
                                     coordinate system. In certain respects we can draw on our knowledge of the latitude-
                                     and-longitude system of locating a place on the surface of the earth, but usually we
                                     consider only points on the surface and not those below or above ground.
                                        Let us start by building a spherical coordinate system on the three rectangular
                                     axes (Figure 1.8a). We first define the distance from the origin to any point as r. The
                                     surface r = constant is a sphere.
                                        The second coordinate is an angle θ between the z axis and the line drawn
                                     from the origin to the point in question. The surface θ = constant is a cone, and
                                     the two surfaces, cone and sphere, are everywhere perpendicular along their inter-
                                     section, which is a circle of radius r sin θ. The coordinate θ corresponds to latitude,
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