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CHAPTER 12   Plane Wave Reflection and Dispersion      437


                                                                                           EXAMPLE 12.9
                     Light is incident from air to glass at Brewster’s angle. Determine the incident and
                     transmitted angles.
                     Solution. Because glass has refractive index n 2 = 1.45, the incident angle will be
                                                   
                                                                 1.45
                             θ 1 = θ B = sin −1      n 2    = sin −1  √  = 55.4 ◦
                                                                    2
                                               2
                                              n + n 2 2         1.45 + 1
                                               1
                     The transmitted angle is found from Snell’s law, through
                                                                   

                                θ 2 = sin −1  n 1  sin θ B  = sin −1      n 1    = 34.6 ◦
                                                               2
                                           n 2                n + n 2 2
                                                               1
                     Note from this exercise that sin θ 2 = cos θ B , which means that the sum of the incident
                     and refracted angles at the Brewster condition is always 90 .
                                                                    ◦
                         Many of the results we have seen in this section are summarized in Figure 12.10,
                     in which   p and   s , from (69) and (71), are plotted as functions of the incident
                     angle, θ 1 . Curves are shown for selected values of the refractive index ratio, n 1 /n 2 .
                     For all plots in which n 1 /n 2 > 1,   s and   p achieve values of ±1at the critical angle.
                     At larger angles, the reflection coefficients become imaginary (and are not shown)
                     butnevertheless retain magnitudes of unity. The occurrence of the Brewster angle is
                     evident in the curves for   p (Figure 12.10a) because all curves cross the θ 1 axis. This
                     behavior is not seen in the   s functions because   s is positive for all values of θ 1
                     when n 1 /n 2 > 1.

                        D12.5. In Example 12.9, calculate the reflection coefficient for s-polarized
                        light.

                        Ans. −0.355


                     12.7 WAVE PROPAGATION
                             IN DISPERSIVE MEDIA
                     In Chapter 11, we encountered situations in which the complex permittivity of the
                     medium depends on frequency. This is true in all materials through a number of pos-
                     sible mechanisms. One of these, mentioned earlier, is that oscillating bound charges
                     in a material are in fact harmonic oscillators that have resonant frequencies associated
                     with them (see Appendix D). When the frequency of an incoming electromagnetic
                     wave is at or near a bound charge resonance, the wave will induce strong oscilla-
                     tions; these in turn have the effect of depleting energy from the wave in its original
                     form. The wave thus experiences absorption, and it does so to a greater extent than
                     it would at a frequency that is detuned from resonance. A related effect is that the
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