Page 521 - Engineering Electromagnetics, 8th Edition
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CHAPTER 13   Guided Waves              503

                     which we now apply to (155), whose right-hand side becomes zero when w = 0. This
                     leads to cutoff values of u and V (u c and V c ), and, by (156), u c = V c . Eq. (155) at
                     cutoff now becomes:

                                                 J  −1 (V c ) = 0                   (157)

                     Finding the cutoff condition for a given mode is now a matter of finding the appro-
                     priate zero of the relevant ordinary Bessel function, as determined by (157). This
                     gives the value of V at cutoff for that mode.
                         Forexample, the lowest-order mode is the simplest in structure; therefore it has no
                     variations in φ and one variation (one maximum) in ρ. The designation for this mode
                     is therefore LP 01 , and with   = 0, (157) gives the cutoff condition as J −1 (V c ) = 0.
                     Because J −1 = J 1 (true only for the J 1 Bessel function), we take the first zero of J 1 ,
                     which is V c (01) = 0. The LP 01 mode therefore has no cutoff and will propagate at the
                     exclusion of all other modes provided V for the fiber is greater than zero but less than
                     V c for the next-higher-order mode. By inspecting Figure 13.22a,we see that the next
                     Bessel function zero is 2.405 (for the J 0 function). Therefore,  −1 = 0in (156), and
                     so   = 1 for the next-higher-order mode. Also, we use the lowest value of m   (m = 1),
                     and the mode is therefore identified as LP 11 . Its cutoff V is V c (11) = 2.405. If m = 2
                     were to be chosen instead, we would obtain the cutoff V number for the LP 12 mode.
                     We use the next zero of the J 0 function, which is 5.520, or V c (12) = 5.520. In this
                     way, the radial mode number, m, numbers the zeros of the Bessel function of order
                       − 1, taken in order of increasing value.
                         When we follow the reasoning just described, the condition for single-mode
                     operation in a step index fiber is found to be

                                              V < V c (11) = 2.405                  (158)

                     Then, using (156) along with k 0 = 2π/λ,wefind

                                                     2πa
                                                            2
                                            λ>λ c =        n − n 2                  (159)
                                                    2.405   1   2
                     as the requirement on free-space wavelength to achieve single-mode operation in a
                     step index fiber. The similarity to the single-mode condition in the slab waveguide
                     [Eq. (143)] is apparent. The cutoff wavelength, λ c ,is that for the LP 11 mode. Its value
                     is quoted as a specification of most commercial single-mode fiber.
                                                                                           EXAMPLE 13.6
                     The cutoff wavelength of a step index fiber is quoted as λ c = 1.20 µm. If the fiber is
                     operated at wavelength λ = 1.55 µm, what is V ?
                     Solution. Using (156) and (159), we find

                                                λ c        1.20
                                       V = 2.405   = 2.405      = 1.86
                                                λ          1.55
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