Page 287 - Enhanced Oil Recovery in Shale and Tight Reservoirs
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264                            Enhanced Oil Recovery in Shale and Tight Reservoirs


             Now we consider a water-wet rock. Refer to Eq. (9.49), s os > s ws for
          a water-wet rock because the cosine term should be positive. Then the sec-
          ond term of the above numerator is positive. Similarly, for the first term of
          the above numerator, s as > s ws because a rock generally prefers water-
          wet to air-wet; and generally, s oa < s wa ; Thus, the first term is negative.
          Now the numerator has one positive value and one negative value. Then
          cosq wsa e cosq osa could be negative or positive. Therefore, the q wsa measured
          on a water-wet rock may not necessarily be smaller than q osa . That means,
          even q wsa is greater than q osa , the rock may still be possibly water-wet. There-
          fore, we have Conclusion 2:
             In a gas-water-solid system (a gas-liquid system), the water-wetting angle
          cannot be used to determine the wettability; similarly, in a gas-oil-solid sys-
          tem (a gas-liquid system), the oil-wetting angle cannot be used to determine
          the wettability.
             One may think that if the volume of water imbibed into a dry core is
          higher than the oil volume, the rock is water-wet. According to Washburn’s
          (1921) equation, the imbibition velocity of a fluid into a capillary tube of
          radius r is:

                                            2scosq
                                      DF þ         r 2
                                dl            r
                                  ¼                                  (9.54)
                                dt         8ml
          where l is the imbibition distance, F is the potential, t is the imbibition time,
          s is the interfacial tension, m is the phase viscosity, and q is the contact angle.
          For spontaneous imbibition, DF is zero. The imbibition volume can be
          obtained by integrating the preceding equation:
                                          2
                                        p scosqr 5
                                     2
                                   V ¼           t                   (9.55)
                                           2m
             Then the ratio of spontaneous imbibition volume of water to that of oil is
                                       s ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi
                                 V w     s wa cosq wa m o
                                     ¼                               (9.56)
                                  V o    s oa cosq oa m w
             If V w > V o , s wa m o cosq wa > s oa m w cosq oa . Since s wa > s oa , and m o > m w ,
          generally, cosq wa may not be necessarily greater than cosq oa . Thus, the rock is
          not necessarily water-wet. If V w < V o , s wa m o cosq wa < s oa m w cosq oa . Since
          s wa > s oa , and m o > m w , generally, cosq wa must be smaller than cosq oa .
          Thus, the rock is oil-wet.
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