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book   Mobk070    March 22, 2007  11:7








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                                                 CHAPTER 9


                               Sturm–Liouville Transforms






                   Sturm–Liouville transforms include a variety of examples of choices of the kernel function
                   K(s, t) that was presented in the general transform equation at the beginning of Chapter 6. We
                   first illustrate the idea with a simple example of the Fourier sine transform, which is a special
                   case of a Sturm–Liouville transform. We then move on to the general case and work out some
                   examples.


                   9.1    A PRELIMINARY EXAMPLE: FOURIER SINE TRANSFORM
                   Example 9.1. Consider the boundary value problem

                                                 u t = u xx   x ≤ 0 ≤ 1

                   with boundary conditions

                                                  u(0, t) = 0

                                                  u x (1, t) + Hu(1, t) = 0

                   and initial condition

                                                       u(x, 0) = 1

                        Multiply both sides of the differential equation by sin(λx)dx and integrate over the
                   interval x ≤ 0 ≤ 1.

                                          1                     1
                                                  d u       d
                                                   2
                                           sin(λx)    dx =       u(x, t)sin(λx)dx
                                                  dx 2     dt
                                        x=0                   x=0
                        Integration of the left hand side by parts yields

                                   1
                                       2                                               1
                                      d                            du      d
                                        [sin(λx)]u(x, t)dx + sin(λx)  − u    [sin(λx)]
                                     dx 2                          dx     dx          0
                                 x=0
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