Page 272 - Estimators Piping Man Hour Manual

Section Eleven—TECHNICAL INFORMATION 247

Calculate the reaction at R% due to loads in the plane 285(2.146) - 611.610
H-4 to 0 by taking moments about H-4. 8144.867 ft ft
1728(2.646) = 4572.288
7.083K 2»130(Q.333}+5418(2.5)+247(4.958)+285(6) 500(7.146) = 3573.000
- 43.294-13,545+1224.626+1710
= 16,522.916 8145.288 ft ft
R a=2333ft Take moments about RI to solve for H-S,
3.229H-5 = 285( 1.083)+1728(5.875)+500(10.375)
= 308.655+10,152+5187.5
Bz = 130 + 5418 + 247 + 285 - 3747 - 2333ft = 15,648.155
H-5 = 4846ft
Solve for load and location of H-5 by taking moments
about H-5.
2333 (1.083+Z) +285(Jf ) H-5 = 2333 + 285 + 1728 + 500 - 4846ft
- 1728(4.792 -X) +500(4.5+4.792 -X) Summary:
2526.639+2333Z+285X The loads to be supported by each of the seven
-8280.576 -1728X+2250+2396 -500X hangers as determined in the foregoing calculations are
2333Z+285X+ 1728X+500JS: as follows:
=8280.576+2250+2396 -2526.639 H-l = 5065ft
4846X = 10,399.937 H-2 = 4762ft
H-3 = 7979ft
H-4 = 5875ft
Location of ff-5 is tf-l\* + l'-l' or 3'-2f from 0, H-5 = 4846ft
Check
H-6 = 1156ft
2333(3.229) - 7533.257 H-7 = 1800ft