Page 267 - Estimators Piping Man Hour Manual

242 Section Eleven—TECHNICAL INFORMATION

4354
(H-2)"
= 99 + 1550 + 3173 + 1550 + 790 + 477 - 3804
*
= 38351b
. -X2Q11 .MSB' Total load on H-2 = (H-2)' + (H-2)" = 927 +
3835 = 4762ft.

Figure 4
force on H-l due to the line A-(H-l) plus /2#-i reacting
at 0.
3.708(/M)" = 4354(1.*83)+500(3.291)+638(11.166)
= 6892.382+1645.5+7123.908
= 15,661.79
(//-!}" = 4224ft
or
(//-I)" = 4354 + 500 + 638 - 1268 = 4224ft
Totai load on H-l = (H-l)' + (H-l)" = 841 +
4224= 5065ft
Section 2
Consider next the section of pipe between H-2 and
H-3. Figure 5 shows the section in elevation with the
loads indicated as in Figure 2. In this section we will
consider Ra-2, which as yet has not been balanced.
The weight of the vertical bend is considered as
acting at the center of gravity of the bend. Figure 3
can be used to determine this location.
Figure 5
C = 5 X 0.637 = 3.183' = 3'-2j*
All forces are in the vertical plane. Section 3
Take moments about H-2, solve for (H-3)', the load
on #-3 due to the line (H-2)-(H-3). The section of pipe between H-4 and H-5 has an
imposed load of the 6' line through the flanged tee.
14.5(tf-3)' = -477(9) + 790(2) + 1550(7.187) This load must now be detennined and at the same time
+ 3173(9) + 1550(10.183) + 99(14.25) solve for loads on Hangers //-6 and H-7. See Fig-
- -4293 + 1580 + 11,139.85 + 28,557 ure 6.
+ 16,760.15 + 1410.75 The load and the imaginary beam reactions for the
-= 55,154.75 45° bend are calculated as in Section 1. The load due
(H-S)' = 3804ft to line (H-6)-Rn-7 results in the reaction RH-T which
Take moments about H-3 to solve for (H-2)", the is to be carried by H-7. The load due to line
load on H-2 due to line (H-2) to (H-S). Rn-»-(H-7) results in the reaction RH-» which is to be
carried by H-6.
!4.5(ff-2)" •= 99(0.25) + 1550(3.683) + 3173(5.5) Taking moments about H-G solve for RS-I, see
+ 1550(7.317) + 790(12.5) Figure 7.
+ 477(23,5)
- 24.75 + 5708.65 + 17,451.5 2R a. 1 = 62(0.437) + 146(1.208)
+ 11,341.35 + 9875 + 11,209.5 = 27.094 + 176.368
- 55,610.75 = 203.462
(H-2)" « 3835ft R a. 7 = 1021b