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APPENDIX 8     ANSWERS AND COMMENTS FOR PROBLEMS                     43 5



               9.  After evaluating the areas using a trial value of c, Goal Seek.. . was used to
                   set the relationship area bounded by y=4 - 2* area bounded by y  = c  to
                   zero. The changing cell and the target cell are shown on the spreadsheet.  c =
                   2.528.


               10. The same procedure was followed as in the preceding problem.  c = 8.68


               11. Answer = 6.51413 (approx.), n4/15 = 6.493939 (exact).
                                                          -
               12. (a)  Answer: 1    (b)  1  (c)  !h  (d)




               Chapter 8  Roots of Equations


               1.  To find the first time  after t  = 0 when  the current reaches  zero, you  must
                   begin with a value oft that will force Goal Seek to converge to the first i = 0
                   after t = 0.  Using t = 1 is a good choice.  t = 1.576 seconds.


               2.  Use Goal Seek.. . D = 0.756.


               3.  The  spreadsheet  shows  a  manual  method,  similar  to  the  interval-halving
                   method, and also uses Goal Seek.  [Ba2']  = 1.28 x  1 0-5 M.


               4.  The spreadsheet shows the graphical method and also uses Goal Seek.  S =
                   0.13 mol/L.


                5.  Use Goal Seek with Yl-Y2 as target cell formula.  Use two different initial
                   values of x to get the two different x-values.  Formulas are under the chart.
                   Answer: x = -5.857 and x = 12.494.


                6.  Follow same procedure as in the preceding problem.  For h = 0.5, x = -0.87
                   and x = 0.87.  If you use the Goal Seek custom function, you can change the
                   value of h and observe the intersections change.


                7.  This problem requires two successive uses of Goal Seek.  The procedure  is
                   described on the spreadsheet..

                8.  x = 0.288, [A] = 0.4858 mol L-I.
                9.  x = 0.8598, [A] = 0.1402 atm
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