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4.2 Finite Element Method                                  65


                                                 1
                                          A         x     )y   x  (y   )y   x  ( y   y  )y    (
                                                 2   2  3  1    1  2   3    3  1  2
                                 In  the  above  equations,  x i , y i  1, 2, 3 are  coordinates  of  the
                                                               ;
                                                              i
                                 three  nodes.    The  parameters  a b c  i  1, 2, 3 depend  on  the
                                                                   ,
                                                                ,
                                                                      ;
                                                                     i
                                                               i
                                                                  i
                                 nodal coordinates as follows,
                                     a     1  x y   23  x y      b     y   y    c     x   x
                                                                                    3
                                                    32
                                                            1
                                                                                        2
                                                                   2
                                                                       3
                                                                             1
                                     a     2  x y   31  x y    b     y   y    c     x   x
                                                   1 3
                                                            2
                                                                   3
                                                                       1
                                                                             2
                                                                                        3
                                                                                    1
                                     a     3  x y   12  x y    b     y   y    c     x   x
                                                    2 1
                                                                             3
                                                                   1
                                                                       2
                                                                                        1
                                                                                    2
                                                            3
                                            The  finite  element  equations  corresponding  to  the
                                 three-node triangular element above are,
                                                                
                                                         K 
                                                                     F
                                                         
                                                                     
                                                             
                                                        (6 6)  (6 1)  (6 1)
                                 where the element stiffness matrix   can be determined from,
                                                                  K
                                                                T
                                                              t A
                                                     K
                                                                      B
                                                              B
                                                                  C
                                                                      
                                                     
                                                                   
                                                              
                                                    (6 6)    (6 3)  (3 3) (3 6)
                                                              b 1  0   b 2  0  b 3  0  
                                 where             B     1   0  c 1  0  c 2  0  c 3  
                                                  
                                                 (3 6)    2A                      
                                                              c   1   b 1  c 2  b 2  c 3  b  
                                                                                  3
                                                        uv u v u v  
                                                   T
                                                 
                                                            1 
                                                                          3
                                                                       3
                                                                    2
                                                              1
                                                                 2
                                                  
                                                (6 1)
                                 and                   FF   1x  F 2y  F 2x  F 3y  F 
                                                    T
                                                 F
                                                            1 
                                                                                 y 
                                                                                3x
                                                 
                                                (6 1)
                                            Similarly, the finite element equations for the four-node
                                 quadrilateral  element  can  be  determined  in  the  same  way,  except
                                 the process is more complicated.  These element matrices suggest
                                 that it is nearly impossible to solve plane stress problems by hands
                                 even though they contain only few elements.  Developing a finite
                                 element  computer  program  is  thus  required.    A  model  with  few
                                 hundred  elements  can  be  solved  easily  by  using  a  computer
                                 program.    We  will  employ  ANSYS  through  its  Workbench  to
                                 analyze plane stress problems in the following sections.  We will
                                 find  that  the  software  can  provide  solutions  conveniently  and
                                 effectively for model containing a large number of elements.
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