Page 510 - Fluid-Structure Interactions Slender Structure and Axial Flow (Volume 1)
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480               SLENDER STRUCTURES AND AXIAL FLOW

                      Therefore,  the  overall  conclusion  is  that,  except  for  extreme  conditions,  either  set
                    of  equations may  be  used - leaving  aside  the  thorny  question  as to  which  set  is  the
                    correct one.


                    E.2  THE EIGENFUNCTIONS OF A TIMOSHENKO BEAM
                    Neglecting rotatory inertia and flow effects, equations (4.38) reduce to





                    Eliminating q or + from one of these equations, one obtains

                                            a2q
                           a4q   1  a4q   +--0,         a4+    1  a4+     a2+
                                                        __-____
                           ap    A  apat2  at*           at4   A  apat2  +--0,           (E.4)
                                                                          at2
                    and hence the eigenvalue problem associated with just one of them needs to be considered.
                    Letting q = Y (6) exp(iwt), 1c. = W(4) exp(iwt), this is associated with
                                             d4Y   w2 d2Y
                                                 +
                                             - - - w2Y  = 0,
                                                           -
                                              dt4   A  dC2
                    and the same for W. Proceeding as for an Euler-Bernoulli  beam (cf. Section 2.1.3), the
                    solution of (E3 is of  the form

                                    Y  = cosh q$ + B  sinh q5 + C cos p4: + D  sin pt,   (E.6)
                    where





                    and similarly for  ly. After some manipulation, malung use of  (E.3), it is easy to obtaint
                    ‘separated forms’ of boundary conditions (4.39a,b) as follows:
                    (i) displacement zero:
                                             Y = 0    and    @’”  = 0;                  (E.8a)

                    (ii) slope zero:

                                   W=0      and     (~)Y”’+[I+(~)2]y’=o;                (E.8b)

                    (iii) bending moment zero:


                                        W’=  0    and    Y”+                            (E&)


                      +For example, if P = 0, differentiating the first of  (E.3) with respect to 6 and then substituting the second
                    one (with P = 0) into it leads to the second of  (E.8a).
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