Page 115 - Foundations Of Differential Calculus
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98    5. On the Differentiation of Algebraic Functions of One Variable
                       1
          II. Let y = √     ; find the first- and higher-order differentials.
                      1 − x 2
                           dy       x
                              =           ,
                                     2
                           dx   (1 − x ) 3/2
                           2           2
                          d y  =  1+2x    ,
                                     2
                          dx 2  (1 − x ) 5/2
                           3
                          d y    9x +6x 3
                                     2
                          dx 3  =  (1 − x ) 7/2  ,
                           4           2     4
                          d     9+72x +24x
                          dx 4  =  (1 − x ) 9/2  ,
                                        2
                                           3
                           5
                          d y   225x + 600x + 120x 5
                                          2
                          dx 5  =   (1 − x ) 11/2  ,
                           6
                                           2
                                                   4
                          d y   225 + 4050x + 5400x + 720x 6
                                              2
                          dx 6  =        (1 − x ) 13/2      ,
             and so forth. These differentials can easily be continued, but the law
             by which the terms proceed may not be immediately obvious. The
             coefficient of the highest power of x is the product of the natural num-
             bers from 1 to the order of the differential. Meanwhile, if we wish to
                                                                 √
                                                                       2
             continue further our investigation, we will find that if y =1/ 1 − x ,
             generally we have
                 n
                d y   1 · 2 · 3 ··· n
                    =          1
                           2
                dx n  (1 − x ) n+ 2

                              1 n (n − 1)  n−2
                          n
                      × x +     ·        x
                              2    1 · 2
                            1 · 3 n (n − 1) (n − 2) (n − 3)  n−4
                          +     ·                     x
                            2 · 4      1 · 2 · 3 · 4
                            1 · 3 · 5 n (n − 1) ··· (n − 5)  n−6
                          +       ·                  x
                            2 · 4 · 6   1 · 2 ··· 6
                            1 · 3 · 5 · 7 n (n − 1) ··· (n − 7)  n−8
                          +          ·                 x    + ··· .
                            2 · 4 · 6 · 8  1 · 2 ··· 8

        Examples of this kind are useful not only for acquiring a habit of differ-
        entiating, but they also provide rules that are observed in differentials of
        all orders, which are very much worth noticing and can lead to further
        discoveries.
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