Page 190 - Foundations Of Differential Calculus
P. 190

9. On Differential Equations  173
        292. It is particularly important to notice that irrational and transcen-
        dental quantities can be eliminated from an equation by differentiation.
        With regard to irrationals, by known methods of reduction irrationals can
        be eliminated, and once this is accomplished, by differentiation we obtain
        an equation free of any irrationality. However, frequently it can be more
        convenient without the reduction to remove the irrationality by comparing
        the differential equation with the finite formula, provided that there is only
        one irrational quantity. If there are two or more irrational parts in the fi-
        nite equation, then the differential equation is differentiated again as many
        times as there are individual irrational parts to be eliminated, and hence
        the differential equation will be of a higher order. In this way arbitrary
        exponents and fractional exponents can also be eliminated. For example, if
                                        2

                                 y m  = a − x 2    n  ,
        then after differentiation we have
                            m−1            2   2   n−1
                         my    dy = −2n a − x       x dx.
        When this equation is divided by the finite equation we have
                                 mdy      2nx dx
                                      = −       ,
                                          2
                                  y      a − x 2
        in which there remains no arbitrary exponent. It should be clear that a
        differential equation that is free of all irrationality can arise from a finite
        equation that involves an irrationality or even a transcendental quantity.

        293. In order that we understand the way in which transcendental quan-
        tities are eliminated by differentiation we begin with logarithms. Since the
        differential of a logarithm is algebraic, this operation causes no difficulty.
        Thus, if

                                    y = x ln x,
        then y/x =ln x, and by differentiation we have
                                 xdy − ydx  =  dx ,
                                     x 2      x
        so that

                                xdy − ydx = x dx.
        If there are two logarithms, then two differentiations are required. If

                                  y ln x = x ln y,
        then
                                   y ln x
                                        =ln y,
                                     x
   185   186   187   188   189   190   191   192   193   194   195