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166                                                                       Forough Ameli et al.


                5.2.9.3 Forced Convection /L (Normal to Tube)
                The value of heat transfer by convection is calculated as follows:
                                            Q lc 5 2πr 3 h c ðT 3 2 T a Þ             (5.94)
                where h c is the convective heat transfer coefficient based on outer tube diameter.

                                            1000 # N Re # 50; 000
                   To calculate the convective heat transfer coefficient, there are correlations that are
                applicable for covering a wide-spreading range of wind velocities. The following cor-
                relation represented by McAdams [71] may be used for forced convection as a domi-
                nated mechanism of heat transfer.

                                                  0:12k ha  0:6
                                             h fc 5     N Re                          (5.95)
                                                    r 3

                where k ha is the thermal cond. air (Btu/h ft F), h fc is the forced conv. htc (Btu/h ft F).

                   To calculate Reynolds number for air flowing into the pipe, use the following
                correlation:
                                                        r 3 v a ρ a
                                              N Re 5 4365                             (5.96)
                                                          μ a
                                                    3
                where ρ a is the air density at Ta (lbm/ft ), μ a is the air viscosity (cP), v a is the air
                velocity normal to pipe (mi/h), k ha and μ a are calculated at film T 5 (T 3 1 T a )/2. As
                T 3 is unknown, the solution technique would be trial and error.



                5.2.9.4 Radiation Heat Loss/L
                To calculate the value of surface heat transfer by the mechanism of radiation
                (Fig. 5.9), use the following equation:

                                                  4      4      4
                                                                      4
                                    Q 5 πr 3 Eσ½ T 3 2 T sky  1 ðT 3 2 T g Þ          (5.97)
                                     lr













                Figure 5.9 Radiation heat loss.
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