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Some Important Discrete Distributions                           165

             The moments and distribution of X  can be easily found by using Equation
           (6.10). Since

                           EfX j gˆ 0…q†‡ 1…p†ˆ p; j ˆ 1; 2; ... ; n;

           it follows from Equation (4.38) that

                               EfXgˆ p ‡ p ‡     ‡ p ˆ np;               …6:11†

           which is in agreement with the corresponding expression in Equations (6.8).
           Similarly, its variance, characteristic function, and pmf are easily found follow-
           ing our discussion in Section 4.4 concerning sums of independent random
           variables.
             We have seen binomial distributions in Example 3.5 (page 52), Example 3.9
           (page 64), and Example 4.11 (page 96). Its applications in other areas are
           further illustrated by the following additional examples.
             Example 6.1. Problem: a homeowner has just installed 20 light bulbs in a new
           home. Suppose that each has a probability 0.2 of functioning more than three
           months. What is the probability that at least five of these function more than
           three months? What is the average number of bulbs the homeowner has to
           replace in three months?
             Answer: it is reasonable to assume that the light bulbs perform indepen-
           dently.  If  X   is  the  number  of  bulbs  functioning  more  than  three  months
           (success), it has a binomial distribution with n ˆ  20 and p ˆ 0:2.  The answer
           to the first question is thus given by

                 20             4
                 X             X
                    p …k†ˆ 1      p …k†
                     X             X
                 kˆ5           kˆ0
                                4
                               X   20      k    20 k
                         ˆ 1           …0:2† …0:8†
                                    k
                               kˆ0
                         ˆ 1  …0:012 ‡ 0:058 ‡ 0:137 ‡ 0:205 ‡ 0:218†ˆ 0:37:
             The average number of replacements is

                          20   EfXgˆ 20   np ˆ 20   20…0:2†ˆ 16:

             Example 6.2. Suppose that three telephone users use the same number and
           that we are interested in estimating the probability that more than one will use
           it at the same time. If independence of telephone habit is assumed, the prob-
           ability of exactly k persons requiring use of the telephone at the same time is
           given by the mass function p (k) associated with the binomial distribution. Let
                                   X







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