Page 288 - Fundamentals of Probability and Statistics for Engineers
P. 288
Parameter Estimation 271
Answer: let us denote 2 by . Then,
1 X 2
f
X; exp ;
2 1=2 2
and
X 2 1
ln f
X; ln 2 ;
2 2
q ln f
X; X 2 1
;
q 2 2 2
2
q ln f
X; X 2 1
;
q 2 3 2 2
2
q ln f
X; 1 1
E :
q 2 3 2 2 2 2
Hence, according to Equation (9.36), the CRLB for the variance of any
2
unbiased estimator for is 2 /n.
2
For S , it has been shown in Section 9.1.2 that it is an unbiased estimator for
and that its variance is [see Equation (9.10)]
1 n 3 4
2
varfS g 4
n n 1
1 n 3
4
3 4
n n 1
2 4 2 2
;
n 1 n 1
2
since 4 3 4 when X is normally distributed. The efficiency of S , denoted by
2
e(S ), is thus
CRLB n 1
2
e
S :
2
var
S n
We see that the sample variance is not an efficient estimator for in this
case. It is, however, asymptotically efficient in the sense that e(S 2 ) 1 as!
n !1.
TLFeBOOK