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MATERIAL BALANCE APPLIED TO OIL RESERVOIRS                          82

                     gas in the reservoir the total reservoir system compressibility in the simple material
                     balance

                           dV = cV ∆p


                     will be greatly increased by the presence of the gas and the dV, which is the
                     production, will be large for a given pressure drop.


                                          N p
                                                   %
                                          N    900
                                            50



                                            40




                                            30



                                            20



                                            10



                                             0
                                               0      1000    2000    3000     4000
                                                           R (scf / stb)
                                                             p
                     Fig. 3.3   Oil recovery, at 900 psia abandonment pressure (% STOIIP), as a function of
                                the cumulative GOR, R p  (Exercise 3.2)

               2)    The free gas saturation in the reservoir may be deduced in two ways, the most obvious
                     being to consider the overall gas balance


                             liberated              total                  gas                 gasstill
                             gasinthe              amount               producedat            dissolved
                                         =                     −                       −
                               reservoir              of gas              thesurface             intheoil



                     which in terms of the basic PVT parameters can be evaluated at any reservoir pressure
                     as


                     liberated gas (rb)  =  (NR si – N pR p − (N − N p) R s) B g
                     and expressing this as a saturation, which is conventionally required as a fraction of
                     the pore volume, then


                             S g  =  [ N (R si − R s) − N p (R p − R s) ] B g (1 − S wc) / NB oi    (3.21)
                     where    NB oi / (1 − S wc) = HCPV / (1 − S wc) = the pore volume.
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