Page 19 - Fundamentals of The Finite Element Method for Heat and Fluid Flow
P. 19

INTRODUCTION
                           A Taylor series expansion results in
                                                                ∂Q x                           11
                                                  Q x+dx = Q x +     x
                                                                 ∂x
                                                                ∂Q y
                                                  Q y+dy = Q y +     y
                                                                 ∂y
                                                                ∂Q z
                                                   Q z+dz = Q z +   z                       (1.32)
                                                                ∂z
                           Note that the second- and higher-order terms are neglected in the above equation. The
                        heat generated in the control volume is G x y z and the rate of change in energy storage
                        is given as
                                                                 ∂T
                                                      ρ x y zc p                            (1.33)
                                                                 ∂t
                           Now, with reference to Figure 1.4, we can write the energy balance as

                        inlet energy + energy generated = energy stored + exit energy
                           that is,
                                                               ∂T
                           G x y z + Q x + Q y + Q z = ρ x y z    + Q x+dx + Q y+dy + Q z+dz  (1.34)
                                                                ∂t
                           Substituting Equation 1.32 into the above equation and rearranging results in

                                ∂Q x      ∂Q y     ∂Q z                            ∂T
                              −      x −       y −      z + G x y z = ρc p  x y z           (1.35)
                                 ∂x       ∂y        ∂z                             ∂t
                           The total heat transfer Q in each direction can be expressed as

                                                                       ∂T
                                               Q x =  y zq =−k x  y z
                                                           x
                                                                       ∂x
                                                                       ∂T
                                               Q y =  x zq =−k y  x z
                                                           y
                                                                       ∂y
                                                                       ∂T
                                               Q z =  x yq =−k z  x y                       (1.36)
                                                           z
                                                                       ∂z
                           Substituting Equation 1.36 into Equation 1.35 and dividing by the volume,  x y z,
                        we get
                                      ∂     ∂T     ∂     ∂T     ∂     ∂T         ∂T
                                         k x   +     k y    +     k z   + G = ρc p          (1.37)
                                     ∂x    ∂x     ∂y    ∂y    ∂z    ∂y            ∂t
                           Equation 1.37 is the transient heat conduction equation for a stationary system expressed
                        in Cartesian coordinates. The thermal conductivity, k, in the above equation is a vector. In
                        its most general form, the thermal conductivity can be expressed as a tensor, that is,

                                                                   
                                                         k xx k xy k xz
                                                    k =    k yx k yy k yz                 (1.38)
                                                         k zx k zy k zz
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