Page 252 - Fundamentals of The Finite Element Method for Heat and Fluid Flow
P. 252

244
                        fractional area a f may vary from location to location on the macro-length scale ‘L’ of the
                        physical problem owing to the variation of the bed porosity.
                           The porosity,  , of the medium is defined as  CONVECTION IN POROUS MEDIA
                                                 void volume   a f  x 1  x 2
                                               =            =           = a f               (8.10)
                                                 total volume   x 1  x 2
                           Now, the mass balance of an arbitrary control volume, as shown in Figure 8.3, gives
                        (refer to Chapter 7)
                                                ∂ρ f  ∂(ρ f u 1f )  ∂(ρ f u 2f )
                                                   +         +        = 0                   (8.11)
                                                ∂t     ∂x 1      ∂x 2
                        where the subscript ‘f’ stands for fluid, ρ is the density and u 1 and u 2 are the velocity com-
                        ponents in the x 1 and x 2 directions respectively. The volume averaged velocity components
                        may be defined as (Nield and Bejan 1992),

                                                                                            (8.12)
                                                   u 1 =  u 1f  u 2 =  u 2f
                           Equation 8.11 can be simplified for an incompressible flow (constant density) as
                        follows:
                                                      ∂u 1  ∂u 2
                                                          +     = 0                         (8.13)
                                                      ∂x 1  ∂x 2
                           Similarly, the equation for momentum balance can be derived. For instance, in the x 2
                        direction, the momentum balance gives
                                                                2  !
                                   ρ f  ∂u 2  ∂     u 1 u 2     ∂  u 2
                                           +            +           =
                                        ∂t   ∂x 1         ∂x 2
                                                                    !
                                                                 2
                                                          2
                                         1 ∂         µ e  ∂ u 2  ∂ u 2
                                       −      (p f  ) +    2  +   2   + (ρ ref − ρ f )g − D x 2  (8.14)
                                           ∂x 2          ∂x     ∂x
                                                           1      2
                        where µ e is the equivalent viscosity, p f the fluid pressure, g the acceleration due to gravity
                               is the matrix drag per unit volume of the porous medium. The particle drag can
                        and D x 2
                        be expressed in the following form, as discussed in Section 8.1:
                                                      D p = aV + bV  2                      (8.15)
                        for a one-dimensional flow with velocity V . For two-dimensional flow, the drag in the x 2
                        direction is given as
                                                                   2 1/2
                                                              2
                                                    = au 2 + b(u + u )                      (8.16)
                                                D x 2         1    2   u 2
                        by resolving the vertical drag expression along the x 2 direction. In the present formulation,
                        Ergun’s correlation for the constants a and b, given in Equations 8.5 and 8.6, will be used.
                                                               can be written as
                           Now, the solid matrix drag component D x 2
                                                     µ f u 2  1.75 ρ f |V|
                                                   =      + √    √                          (8.17)
                                               D x 2                    u 2
                                                      κ       150  κ   3/2
   247   248   249   250   251   252   253   254   255   256   257