Page 257 - Fundamentals of The Finite Element Method for Heat and Fluid Flow
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CONVECTION IN POROUS MEDIA
                           The above simplified equation has been derived by substituting the equation of conti-
                        nuity. Thus, the conservation of mass is satisfied indirectly without explicitly solving for
                        the mass conservation Equation 8.23.                                  249
                           We have a total of three steps to obtain a solution for the momentum and continuity
                        equations. As discussed in Chapter 7, Equation 8.35 is solved at the first step, followed
                        by Equation 8.37 in the second step and Equation 8.36 in the third step. Additional steps,
                        such as temperature or concentration calculations, can be added as an addition to the above
                        three steps.
                           In problems in which non-isothermal and mass transfer effects are involved, additional
                        equations will be solved, after velocity correction. If no coupling exists between the veloc-
                        ities and the other variables, such as temperature and concentration and the steady state
                        solution is only of interest, the steady velocity and pressure fields can be established first,
                        and the rest of the variables can be calculated using the steady state velocity and pressure
                        values.


                        8.3.2 Spatial discretization

                        Once a temporal discretization of the equations has been achieved, then a spatial discretiza-
                        tion may be carried out. In this text, the finite element discretization will be carried out
                        using linear triangular elements. Assuming a Galerkin approximation, the variables can be
                        expressed as


                            u i = [N]{u i };  u i = [N]{ u i };  ˜u i = [N]{ ˜ u i }; p = [N]{p};   = [N]{ }  (8.38)

                        where [N] are the shape functions. We assume that the equations are solved in the order
                        mentioned before, that is, first the intermediate velocity components, then the pressure field
                        and, finally, the velocity correction. On considering the intermediate velocity calculation,
                        we have the following weak form, in which porosity is assumed to be an averaged quantity
                        over an element and body forces are neglected for the sake of simplicity:

                                                                            n
                                   1   T          t         T   ∂     u i
                                     [N]  ˜u i d
 =  −   [N] u j        d
                                  
                     
      ∂x j
                                                               T         n
                                                     1    1 ∂[N] ∂u i
                                                 −                  d
                                                    Re  
   ∂x i ∂x i
                                                                                 n
                                                             t        C   |V|
                                                 −   [N] T      u i + √   3/2  u i  d
 + b.t  (8.39)
                                                    
      ReDa       Da
                        where b.t. represents the boundary integral resulting from an integration by parts of the
                        second-order terms (Green’s lemma, Appendix 1). The weak form of the Step 2 calculation
                        for the pressure field can be written (assuming θ = 1) as

                                                   T
                                          1     ∂[N] ∂( p) n+1    1      T  ∂ ˜u i
                                         −                  d
 =       [N]    d
            (8.40)
                                             
 ∂x i  ∂x i         t  
     ∂x i
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