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4 Monoid Hypersurfaces  69
                              When m =0, one condition must be satisfied for q to be of the form f 4 (θ),
                           namely b 11 =0, where b 11 is the coefficient of st 11  in q.
                              For example, we can have an A 11 singularity only if q is of the form (αs−βt) .
                                                                                            12
                           The condition b 11 =0 implies that either q = λs 12  or q = λt . The first case gives
                                                                            12
                           a surface with a singular line, while the other gives a monoid with an A 11 singularity
                           (see Figure 4.2). The line from O to the A 11 singularity corresponds to the inflection
                           point of Z(f 3 ).
                              For any set of multiplicities m 1 ,...,m r with m 1 +···+m r =12, it is not hard to
                           see that there exist real points p 1 ,...,p r such that the condition b 11 =0 is satisfied.

                           It suffices to take p i =(α i :1), with  m i α i =0 (the condition corresponding to
                           b 11 =0). This completely classifies the possible configurations of singularities when
                           f 3 is a cuspidal curve.
                              Case 3. The tangent cone is the product of a conic and a line that is not tangent
                           to the conic, and we can assume f 3 = x 3 (x 1 x 2 + x ). Then Z(f 3 ) is singular at
                                                                      2
                                                                      3
                           (1 :0:0) and (0 :1:0), the intersections of the conic Z(x 1 x 2 + x ) and the line
                                                                                  2
                                                                                  3
                           Z(x 3 ). For each f 4 we can associate four integers:
                                        j 0 := I (1:0:0) (x 1 x 2 + x ,f 4 ), k 0 := I (1:0:0) (x 3 ,f 4 ),
                                                           2
                                                           3
                                        j 1 := I (0:1:0) (x 1 x 2 + x ,f 4 ), k 1 := I (0:1:0) (x 3 ,f 4 ).
                                                           2
                                                           3
                              We see that k 0 > 0 ⇔ f 4 (1 :0:0)=0 ⇔ j 0 > 0, and that Z(f 4 ) is singular
                           at (1 :0:0) if and only if k 0 and j 0 both are bigger than one. These cases imply
                           a singular line on the monoid, and are not considered in this article. The same holds
                           for k 1 , j 1 and the point (0 :1:0).
                              Define r i = max(j i ,k i ) for i =1, 2. Then, by [19], O will be a singularity of
                                                                     if r 0 ≥ r 1 .
                                          if r 0 ≤ r 1 ,oroftype T 3,4+r 1 ,4+r 0
                           type T 3,4+r 0 ,4+r 1
                              We can parameterize the line Z(x 3 ) by θ 1 where θ 1 (s, t)=(s, t, 0), and the conic
                           Z(x 1 x 2 + x ) by θ 2 where θ 2 (s, t)=(s , −t ,st). Similarly to the previous cases,
                                                            2
                                                                2
                                     2
                                     3
                           roots of f 4 (θ 1 ) correspond to intersections between Z(f 4 ) and the line Z(x 3 ), while
                           roots of f 4 (θ 2 ) correspond to intersections between Z(f 4 ) and the conic Z(x 1 x 3 +
                           x ).
                            2
                            3
                              For any legal values of of j 0 , j 1 , k 0 and k 1 , parameter points
                                                             ) ∈ P \{(0 : 1), (1 : 0)},
                                                                 1
                                       (α 1 : β 1 ),..., (α m r  : β m r
                           with multiplicities m 1 ,...,m r such that m 1 +···+m r =4−k 0 −k 1 , and parameter
                           points

                                       (α : β ),..., (α   m   : β m   ) ∈ P \{(0 : 1), (1 : 0)},


                                                                 1
                                          1  1         r    r

                           with multiplicities m ,...,m   such that m + ··· + m   =8 − j 0 − j 1 , we can fix



                                                   r
                                                                        r
                                            1                 1
                           polynomials q 1 and q 2 such that
                           •  q 1 is nonzero, of degree 4, and has factors s , t  k 0  and (β i s − α i t) m i  for i =
                                                                  k 1
                              1,...,r,



                           •  q 2 is nonzero, of degree 8, and has factors s , t  j 0  and (β s − α t) m i for i =
                                                                  j 1
                                                                              i    i
                              1,...,r .
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