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Direct Use of Geothermal Resources                                          215


              Heat loss via convection is

                             Q  = (9.045 × v) × A × dt
                              cv
                                                      2
                             Q  = (9.045 × 1.0 m/s) × 150 m  × 17 K
                              cv
                               Q  = 6,407 J/s.
                                 cv
              Heat loss via radiation is

                             Q  = ε × σ × A × (T  − T )
                                                  4
                                             4
                                             1
                                                 2
                              rd
                                                    2
                                               −8
                            Q  = 0.99 × 5.669 × 10  W/m K  × 150 m  × (300 K  − 283 K )
                                                      4
                                                                      4
                                                                              4
                                                              2
                             rd
                               Q  = 14,191 J/s.
                                 rd
              Heat loss via evaporation is
                                             b
                              Q  = a × (P  − P )  × H w
                               ev
                                       w
                                           a
                              Q  = 196.88 × (3.7 kPa − 1.23 kPa) 1.068
                                ev
                               Q  = 52,575 J/s.
                                 ev
              The total heat loss, Q  is thus
                               TL
                         Q  = 37,800 J/s + 6,407 J/s + 14,191 J/s + 52,575 J/s = 110, 973 J/s.
                          TL
              This heat loss value overestimates the average load on the facility for several reasons. The heat
            lost by conduction will decrease over time because the thermal gradient driving conduction will
            diminish as the ground around the pond heats up. This term will eventually become negligible and
            can be ignored for long-term considerations, but must be considered during the start-up phase of the
            operation. In addition, the calculation was made for winter conditions and a modest breeze. Neither
            of these conditions is likely to be the average condition for the pond. Under average conditions it can
            thus be assumed that the actual heat loss will be significantly less than computed.
              Managing the flow of water into the pond requires balancing the rate at which fresh water
            needs to be added to the facility to keep the stock healthy, and the addition of heat to maintain
            temperature. Using the heat loss computed above as the actual rate at which make-up heat must
            be added to keep the pond at 27°C, we can compute the inflow rate as a function of the resource
            temperature from

                                          F  = Q /(C  × (T  − T ),                    (11.11)
                                               L
                                                   p
                                                       G
                                           in
                                                           P
            where F  is the rate at which fluid must be added, in l/s, Q  is the total heat loss, C  is the constant
                                                                              p
                  in
                                                           L
            pressure heat capacity of water, T  is the temperature of the geothermal fluid, and T  is the tempera-
                                      G
                                                                              P
            ture of the pond. Plotted in Figure 11.8 is the rate at which fluid must be added to keep the pond at
            27°C, as a function of the temperature of the incoming fluid. The curve in the figure indicates that
            the amount of geothermal water that needs to be added to the pond is very high if the geothermal
            water temperature is within about 15–20° of the pond temperature. Beyond that point, the amount of
            make-up fluid that must be added changes at a relatively small rate over a broad range of geothermal
            water temperatures. This is often considered a rule of thumb for applications such as this (Rafferty
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