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4.2. Equations Whose Kernels Contain Exponential
                      Functions

                 4.2-1. Kernels Containing Exponential Functions


                                b
                                      βt
               1.    y(x) – λ  (e βx  + e )y(t) dt = f(x).
                             a
                     The characteristic values of the equation:
                                                           β
                                       λ 1,2 =                             .
                                             e βb  – e βa  ±  1  β(b – a)(e 2βb  – e 2βa )
                                                         2
                      ◦
                     1 . Solution with λ ≠ λ 1,2 :
                                              y(x)= f(x)+ λ(A 1 e βx  + A 2 ),

                     where the constants A 1 and A 2 are given by


                                f 1 – λ f 1 ∆ β – (b – a)f 2        f 2 – λ(f 2 ∆ β – f 1 ∆ 2β )
                        A 1 =  
                        ,  A 2 =  
                       ,
                                                                    2
                                 2
                             λ ∆ – (b – a)∆ 2β – 2λ∆ β +1      λ ∆ – (b – a)∆ 2β – 2λ∆ β +1
                                                                 2
                              2
                                 β                                  β
                                      b               b                 1

                                                                                βa
                                f 1 =  f(x) dx,  f 2 =  f(x)e βx  dx,  ∆ β =  (e βb  – e ).
                                     a               a                  β
                      ◦
                     2 . Solution with λ = λ 1 ≠ λ 2 and f 1 = f 2 =0:

                                                                      e 2βb  – e 2βa
                                                                βx
                                   y(x)= f(x)+ Cy 1 (x),  y 1 (x)= e  +         ,
                                                                       2β(b – a)
                     where C is an arbitrary constant and y 1 (x) is an eigenfunction of the equation corresponding
                     to the characteristic value λ 1 .
                      ◦
                     3 . Solution with λ = λ 2 ≠ λ 1 and f 1 = f 2 =0:

                                                                      e 2βb  – e 2βa
                                                                βx
                                   y(x)= f(x)+ Cy 2 (x),  y 2 (x)= e  –         ,
                                                                       2β(b – a)
                     where C is an arbitrary constant and y 2 (x) is an eigenfunction of the equation corresponding
                     to the characteristic value λ 2 .
                     4 . The equation has no multiple characteristic values.
                      ◦
                                b
                                      βt
               2.    y(x) – λ  (e βx  – e )y(t) dt = f(x).
                             a
                     The characteristic values of the equation:

                                                            β
                                      λ 1,2 = ±                              .
                                                           1
                                                     βa 2
                                               (e βb  – e ) – β(b – a)(e 2βb  – e 2βa )
                                                           2

                 © 1998 by CRC Press LLC









               © 1998 by CRC Press LLC
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