Page 566 - Handbook Of Integral Equations
P. 566

β
                 11.8-3. Equation With the Kernel K(x, t)= t Q(xt) on the Semiaxis
               Consider the following equation on the semiaxis:


                                                ∞
                                                   β
                                         y(x) –   t Q(xt)y(t) dt = f(x).                   (25)
                                                0
               To solve this equation, we apply the Mellin transform. On multiplying Eq. (25) by x s–1  and
               integrating with respect to x from zero to infinity, we obtain


                            ∞              ∞           ∞                ∞
                                                 β
                              y(x)x s–1  dx –  y(t)t dt  Q(xt)x s–1  dx =  f(x)x s–1  dx.  (26)
                           0               0          0                0
               Let us make the change of variables z = xt.We finally obtain


                                                    ∞
                                               ˆ
                                                                 ˆ
                                         ˆ y(s) – Q(s)  y(t)t β–s  dt = f(s).              (27)
                                                   0
               Taking into account the relation


                                             ∞
                                               y(t)t β–s  dt = ˆy(1 + β – s),
                                            0
               we rewrite Eq. (27) in the form

                                                                ˆ
                                                ˆ
                                           ˆ y(s) – Q(s) ˆy(1 + β – s)= f(s).              (28)
               On replacing s by 1 + β – s in Eq. (28), we obtain

                                                ˆ
                                                                ˆ
                                     ˆ y(1 + β – s) – Q(1 + β – s) ˆy(s)= f(1 + β – s).    (29)
               Let us eliminate ˆy(1 + β – s) and solve the resulting equation for ˆy(s). We thus find the transform of
               the solution:
                                                 ˆ
                                                          ˆ
                                                      ˆ
                                                f(s)+ Q(s)f(1 + β – s)
                                          ˆ y(s)=                  .                       (30)
                                                        ˆ
                                                     ˆ
                                                 1 – Q(s)Q(1 + β – s)
                   On applying the Mellin inversion formula, we obtain the solution of the integral equation (25)
               in the form
                                                   f(s)+ Q(s)f(1 + β – s)
                                          1     c+i∞ ˆ   ˆ   ˆ         –s
                                   y(x)=                              x ds.                (31)
                                                           ˆ
                                                       ˆ
                                         2πi        1 – Q(s)Q(1 + β – s)
                                             c–i∞
                   Remark 2. The equation

                                                ∞
                                                        p q
                                        y(x) –    H(xt)x t y(t) dt = f(x)
                                               0
                                                                     p
               can be rewritten in the form of Eq. (25) under the notation Q(z)= z H(z), where β = q – p.

                 © 1998 by CRC Press LLC








               © 1998 by CRC Press LLC
                                                                                                             Page 549
   561   562   563   564   565   566   567   568   569   570   571