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which can be rewritten in the form
                                                          2
                                        (µ – 1)(2µ – 1)(5µ – 1)(13µ – 22µ + 1)=0.          (16)
               On solving (16), we obtain

                                  ˜ λ 1 = 10.02,  ˜ λ 2 = 43.2,  ˜ λ 3 = 108,  ˜ λ 4 = 216,  ˜ λ 5 = 355.2.
                   The exact values of the characteristic values of the equation under consideration are known:
                                                    2
                                  2
                                                                      2
                              λ 1 = π = 9.869 ... ,  λ 2 =(2π) = 39.478 ... ,  λ 3 =(3π) = 88.826 ... ,
               and hence the calculation error is 2% for the first characteristic value, 9% for the second characteristic value, and 20% for
               the third characteristic value.
                   The result can be improved by choosing another collection of points x i and t i (i =1, ... , 5). However, for this number
               of ordinates we cannot have very high precision, because the kernel Q(x, t) itself has a singularity, namely, its derivative is
               discontinuous for x = t, and thus the kernels under consideration cannot provide a good approximation of the given kernel.
                •
                 References for Section 11.14: H. Bateman (1922), E. Goursat (1923), L. V. Kantorovich and V. I. Krylov (1958).


               11.15. The Collocation Method

                 11.15-1. General Remarks

               Let us rewrite the Fredholm integral equation of the second kind in the form

                                                     b

                                    ε[y(x)] ≡ y(x) – λ  K(x, t)y(t) dt – f(x) = 0.          (1)
                                                    a
               Let us seek an approximate solution of Eq. (1) in the special form


                                            Y n (x)= Φ(x, A 1 , ... , A n )                 (2)

               with free parameters A 1 , ... , A n (undetermined coefficients). On substituting the expression (2)
               into Eq. (1), we obtain the residual


                                                       b

                                    ε[Y n (x)] = Y n (x) – λ  K(x, t)Y n (t) dt – f(x).     (3)
                                                      a
               If y(x) is an exact solution, then, clearly, the residual ε[y(x)] is zero. Therefore, one tries to
               choose the parameters A 1 , ... , A n so that, in a sense, the residual ε[Y n (x)] is as small as possible.
               The residual ε[Y n (x)] can be minimized in several ways. Usually, to simplify the calculations, a
               function Y n (x) linearly depending on the parameters A 1 , ... , A n is taken. On finding the parameters
               A 1 , ... , A n , we obtain an approximate solution (2). If

                                                lim Y n (x)= y(x),                          (4)
                                               n→∞

               then, by taking a sufficiently large number of parameters A 1 , ... , A n ,we find that the solution y(x)
               can be found with an arbitrary prescribed precision.
                   Now let us go to the description of a concrete method of construction of an approximate
               solution Y n (x).




                 © 1998 by CRC Press LLC








               © 1998 by CRC Press LLC
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