Page 275 - Handbook of Civil Engineering Calculations, Second Edition
P. 275

2.60    REINFORCED AND PRESTRESSED CONCRETE ENGINEERING AND DESIGN

                            Calculation Procedure:

                            1. Compute the beam-weight stresses at B
                            In the composite stress diagram, Fig. 35b, the difference between an ordinate to EFG and
                            the corresponding ordinate to AHJ represents the value of f ti at the given section. It is ap-
                            parent that if AE does not exceed HF, then f ti does not exceed HE in absolute value any-
                            where along the span. Therefore, for the center interval BC, the critical stresses at transfer
                            occur at the boundary sections B and C. Analogous observations apply to Fig. 35c.
                              Computing the beam-weight stresses at B yields f bw   ( /4)( 374)   281 lb/sq.in.
                                                                       3
                            ( 1937.5 kPa); f tw   281 lb/sq.in. ( 1937.5 kPa).
                            2. Tentatively set the critical stresses equal to their allowable
                            values to secure the allowable unit superimposed load
                            Thus, at B: f bi   f bp   281   2400; f ti   f tp   281   190; f bp   2681 lb/sq.in.
                            ( 18,485.5 kPa); f tp   471 lb/sq.in. ( 3247.5 kPa).
                              At M: f bf   0.85(2681)  374   f bs   425; f tf   0.85( 471)   374   f ts   2250;
                            f bs   2330 lb/sq.in. ( 16,065.4 kPa); f ts   2277 lb/sq.in. ( 15,699.9 kPa). The latter
                            value controls.
                              Also, w s   83(2277/374)   505 lb/lin ft (7369.9 N/m); 505/452   1.12. The capacity
                            is increased 12 percent.
                              When the foregoing calculations are compared with those in the previous calculation
                            procedure, the effect of deflecting the tendons is to permit an increase of 281 lb/sq.in.
                            (1937.5 kPa) in the absolute value of the prestress at top and bottom. The accompanying
                            increase in f ts is 0.85(281)   239 lb/sq.in. (1647.9 kPa).
                            3. Find the minimum prestressing force and the eccentricity e 1
                            Examination of Fig. 34 shows that  f cai is not affected by the form of trajectory used.
                            Therefore, as in the previous calculation procedure, F i   85,920 lb (382,172.2 N); f tp
                            1074   85,920e 1 /133   471; e 1   2.39 in. (60.706 mm).
                              Although it is not required, the value of f bp   1074   1074   ( 471)   2619
                            lb/sq.in. ( 18,058kPa), or f bp   2681   53/0.85   2619 lb/sq.in. ( 18,058kPa).
                            4. Establish the allowable range of values of e 2
                            At the supports, the tendons may be placed an equal distance above or below the center.
                            Then e 2,max   1.96 in. (23.44 mm); e 2,min   1.96 in. ( 23.44 mm).



                            BEAM WITH CURVED TENDONS

                            The beam in the second previous calculation procedure is to be prestressed by tendons
                            lying in a parabolic arc. Evaluate the allowable unit superimposed load, the magnitude of
                            the prestressing force, the eccentricity of this force at midspan, and the increase in capac-
                            ity accruing from the use of curved tendons.

                            Calculation Procedure:

                            1. Tentatively set the initial and final stresses at midspan
                            equal to their allowable values to secure the allowable unit
                            superimposed load
                            Since the prestressing force has a parabolic trajectory, lines EFG in Fig. 35b and c will be
                            parabolic in the present case. Therefore, it is possible to achieve the full allowable initial
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