Page 560 - Handbook of Electrical Engineering
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552    HANDBOOK OF ELECTRICAL ENGINEERING

                    Find the following:-

                                                           ◦
                                                    ◦
              1. Ideal compressor outlet temperature T 2 in Kand C.
                                                       ◦
                                                 ◦
              2. Ideal turbine outlet temperature T 4 in Kand C.
              3. Ideal cycle efficiency η i in per unit.
                                                 ◦
                                                       ◦
              4. Compressor outlet temperature T 2e in Kand C.
                                             ◦
                                                    ◦
              5. Turbine outlet temperature T 4e in Kand C due to expansion efficiency η t .
              6. Practical cycle efficiency η p per unit, with η c and η t included.
              7. Find the pressure ratio r p max that causes the maximum power to be delivered to the generator.
              F.3 DETAILED REQUIREMENTS
              Assume the specific heats are functions of temperature and take account of the pressure drops  P 1 ,
               P 23 and  P 4 .
                    Find the following:-
                                                  ◦
                                                         ◦
               8. Compressor outlet temperature T 2ea in Kand C, due to compression efficiency η c and the inlet
                  pressure drop  P 1 .
                                                       ◦
                                                ◦
               9. Turbine outlet temperature T 4ea in Kand C, due to expansion efficiency η t , the combustion
                  pressure drop  P 23 , and the outlet pressure drop  P 4 .
              10. The work done on the mass flow to produce the desired output power of 12 MW.
              11. Theoretical thermal efficiency η pa per unit, with all the losses included.
              12. Overall thermal efficiency η pao with all losses included.


              F.4 BASIC SOLUTIONS
              Step 1.  From (2.14),

                                              δ = (1.0 − 1.4)/1.4 =−0.2857
                                              δ
                                        (P 2 /P 1 ) = 11.0 −0.2857  = 0.50403
              Therefore,
                                                                        ◦
                                                                                   ◦
                           T 2 = T 1 /0.50403 = (273.0 + 20.0)/0.50403 = 581.31 K or 308.31 C.
              Step 2.  From (2.15),
                                                 δ
                                          (P 3 /P 4 ) = 11.0 −0.2857  = 0.50403
              Therefore,
                                                                          ◦          ◦
                         T 4 = T 3 × 0.50403 = (273.0 + 950.0) × 0.50403 = 616.43 K or 343.43 C.
              Step 3.
                                              δ
                                             r = 11.0 −0.2857  = 0.50403
                                              p
              and
                                               β
                                              r = 11.0 +0.2857  = 1.984
                                              p
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