Page 219 - Handbook of Energy Engineering Calculations
P. 219

Next, assume a size for the cooling-water piping. Experience shows that a
               water velocity of 300 to 600 ft/min (91.4 to 182.9 m/min) is satisfactory for
               internal-combustion engine cooling systems. Using the Hydraulic Institute’s
               Pipe  Friction  Manual  or  Cameron’s  Hydraulic  Data,  enter  at  280  gal/min
               (17.6 L/s), the approximate flow, and choose a pipe size to give a velocity of

               400 to 500 ft/min (121.9 to 152.4 m/min), i.e., midway in the recommended
               range.
                  Alternatively,  compute  the  approximate  pipe  diameter  from  d  =  4.95
                                          0.5
               [gpm/velocity, ft/min] . With a velocity of 450 ft/min (137.2 m/min), d  =
                                0.5
               4.95(281/450)   =  3.92,  say  4  in  (101.6  mm).  The  Pipe  Friction  Manual
               shows  that  the  water  velocity  will  be  7.06  ft/s  (2.2  m/s),  or  423.6  ft/min

               (129.1  m/min),  in  a  4-in  (101.6-mm)  schedule  40  pipe.  This  is  acceptable.
               Using a 3½-in (88.9-mm) pipe would increase the cost because the size is not
               readily available from pipe suppliers. A 3-in (76.2-mm) pipe would give a
               velocity of 720 ft/min (219.5 m/min), which is too high.



               3. Compute the piping-system head loss
               Examine Fig. 7, which shows the cooling-system piping layout. Three flow
               conditions  are  possible:  (a)  all  the  jacket  water  passes  through  the  heat
               exchanger,  (b)  a  portion  of  the  jacket  water  passes  through  the  heat
               exchanger, and (c) none of the jacket water passes through the heat exchanger

               —instead, all the water passes through the bypass circuit. The greatest head
               loss  usually  occurs  when  the  largest  amount  of  water  passes  through  the
               longest circuit (or flow condition a). Compute the head loss for this situation

               first.
                  Using the method given in the piping section of this handbook, compute
               the equivalent length of the cooling-system fitting and piping, as shown in
               Table  8.  Once  the  equivalent  length  of  the  pipe  and  fittings  is  known,
               compute the head loss in the piping system, using the method given in the

               piping section of this handbook with a Hazen-Williams constant of C = 130
               and a rounded-off flow rate of 300 gal/min (18.9 L/s). Summarize the results
               as shown in Table 8.

                  The  total  head  loss  is  produced  by  the  water  flow  through  the  piping,
               fittings, engine, three-way valve, and heat exchanger. Find the head loss for
               the last components in Fig. 8 for a flow of 300 gal/min (18.9 L/s). List the
               losses in Table 8, and find the sum of all the losses. Thus, the total circuit
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