Page 290 - Handbook of Energy Engineering Calculations
P. 290

2
               where A = cross-sectional area of stream, m  or ft          2


               The axial force on a turbine wheel operating at maximum efficiency where V                   e
               = 1/3 V  is given by
                        i






                  The  axial  forces  are  proportional  to  the  square  of  the  diameter  of  the
               turbine wheel, which makes them difficult to cope with in extremely large-

               diameter  machines.  There  is  thus  an  upper  limit  of  diameter  that  must  be
               determined by design and economical considerations.


               CHOICE OF WIND-ENERGY CONVERSION SYSTEM




               Select  a  wind-energy  conversion  system  to  generate  electric  power  at
               constant  speed  and  constant  frequency  in  a  sea-level  area  where  winds
               average  18  mi/h  (29  km/h),  a  cut-in  speed  of  8  mi/h  (13  km/h)  is  sought,
               blades will be fully feathered (cut out) at wind speeds greater than 60 mi/h

               (100 km/h), and the system must withstand maximum wind velocities of 150
               mi/h  (240  km/h).  Determine  typical  costs  which  might  be  expected.  The
               maximum rotor diameter allowable for the site is 125 ft (38 m).



               Calculation Procedure:


               1. Determine the total available wind power
               Figure 1 shows the total available power in a freely flowing windstream at
               sea  level  for  various  wind  speeds  and  cross-sectional  areas  of  windstream.
               Since  the  maximum  blade  diameter,  given  that  a  blade-type  conversion
               device will be used, is 125 ft (38 m), the area of the windstream will be A =

                                                                    2
                                  2
                                                      2
                  2
               πd /4 = π (125) /4 = 12,271.9 ft  (1140.1 m ). Entering Fig. 1 at this area and
               projecting vertically to a wind speed of 18 mi/h (29 km/h), we see that the
               total available power is 200 kW.
   285   286   287   288   289   290   291   292   293   294   295