Page 39 - Handbook of Energy Engineering Calculations
P. 39

In  this  calculation,  the  molecular-weight  ratio  is  obtained  from  the

               equation for the combustion chemical reaction, or CH  + 2O  = CO  + 2H O,
                                                                                                 2
                                                                                                         2
                                                                                4
                                                                                        2
               that is, 16 + 64 = 44 + 36, and C H  + 7/2O  = 2CO  + 3H O , that is 30 +
                                                                                2
                                                                      2
                                                        2 6
                                                                                         2 2
               112 = 88 + 54. See Table 2 from these and other useful chemical reactions in
               combustion.
                          TABLE 2 Chemical Reactions























               2. Compute the weight of air required for perfect combustion
               The  weight  of  nitrogen  associated  with  the  required  oxygen  =  (3.742)
               (0.768/0.232) = 12.39 lb (5.576 kg). The weight of air required = 12.39 +

               3.742 = 16.132 lb/lb (7.259 kg/kg) of gas burned.


               3. Compute the weight or the products of combustion
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