Page 35 - Handbook of Energy Engineering Calculations
P. 35

Using the molecular weight of each element, we find





















               2. Compute the weight of air required for perfect combustion
               The  weight  of  nitrogen  associated  with  the  required  oxygen  =  (3.1593)
               (0.768/0.232) = 10.458 lb (4.706 kg). The weight of air required = 10.4583 +

               3.1593 = 13.6176 lb/lb (6.128 kg/kg) of oil burned.


               3. Compute the weight of the products of combustion
               As before,


















               4. Convert the flue-gas weight to volume
               As before,
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