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5.2. MATRICES AND DETERMINANTS                     181

                          These elementary transformations are accomplished with the help of elementary matri-
                       ces obtained from the unit matrix by the corresponding operations with its rows (columns).
                       With the help of elementary transformations, an arbitrary matrix A of rank r > 0 can be
                       reduced to normal (canonical) form, which has a block structure with the unit matrix I of
                       size r × r in the top left corner.
                          Example 1. The LU-decomposition of a matrix
                                                           (  214  )
                                                       A =   321
                                                             133

                       can be obtained with the help of the following sequence of elementary transformations:
                               S 1                    S 2                     S 3

                          (  1/200  )(  214  )   (  1  0 0  )(  11/2  2  )  (  1  0 0  )(  11/2  2  )
                             0  1 0    321     → –310        3   2   1  →   0  1 0    01/2   –5  →
                             0  0 1    133         0   0 1   1   3   3     –1  0 1    1  3   3
                                              T 1                       T 2


                              11/2    2   1  –1/2  0     1   0   2   10 –2
                            (          ) (    	    )    (         ) (   	    )
                              01/2   –5   0   1          0  1/2 –5   01    0
                          →                       0 →                         →
                              05/2    1   0   0   1      0  5/2  1   00    1
                                S 4                      S 5
                             10    0   1  0    0      1   0   0   1  0    0

                            (       )(          )   (          )(           )
                          → 02     0   01/2   –5  → 0     1   0   0  1   –10  →
                             00    1   05/2    1      0 –5/2  1   05/2    1
                                            T 3          S 6


                              10    0    10    0      10    0     10    0      100
                            (         ) (   	    )      (  	   )(        )    (       )
                              01 –10     0110 → 01          0     01    0      010
                          →                                                →            .
                              00    26   00    1      001/26      0026         001
                          These transformations amount to the equivalence transformation I = SAT,where T = T 1T 2T 3:
                                               1/2    0     0                      1 –1/2  –7
                                             (                )                  (           )
                             S = S 6S 5S 4S 3S 2S 1 =  –3  2  0   and T = T 1T 2T 3 =  0  1  10  .
                                               7/26  –5/26  1/26                   0   0   1
                       Hence, we obtain
                                               2   0   0                  11/2    2
                                             (          )               (           )
                                          –1                         –1
                                     L = S  =  31/2    0    and U = T  =  0   1  –10  .
                                               15/2   26                  0   0   1
                       5.2.3-2. Similarity transformation.

                       Two square matrices A and A of the same size are said to be similar if there exists a square
                                               2
                       nondegenerate matrix S of the same size, the so-called transforming matrix, such that A
                       and A are related by the similarity transformation
                          2
                                                      –1                 –1
                                                A = S AS     or  A = SAS .
                                                                       2
                                                 2
                          Properties of similar matrices:
                       1. If A and B are square matrices of the same size and C = A + B,then
                                                                        –1
                                                                                 –1
                                                          –1
                                         C = A + B   or  S (A + B)S = S AS + S BS.
                                                 2
                                         2
                                             2
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