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fundamental role in problems involving exponential growth
x
and decay. Observe that lim e = 0 and lim e −x = 0.
x→−∞ x→∞
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−3 −2 −1 1 2 3 −3 −2 −1 1 2 3
f (x) = e x −3 ≤ x ≤ 3 f (x) = e −x −3 ≤ x ≤ 3
Exponential-Growth and Decay
If a substance grows or decays at a rate proportional to its size,
its growth may be described by the equation
dy
= ky
dt
where y is the amount of the substance and k is the constant
of proportionality. Positive values of k correspond to growth
and negative values correspond to decay.
To solve for y, we rewrite the equation in the form
1 dy
= k
y dt
from which it follows by the chain rule that
d
ln y = k
dt
Antidifferentiating, we get
ln y = kt + C
If y = y 0 when t = 0, it follows that ln y 0 = C and we may write
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