Page 167 - How To Solve Word Problems In Calculus
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y(10) = 100e −10 k

                                             75 = 100e −10 k
                                              3
                                                = e −10 k
                                              4

                                                     3
                                          −10k = ln
                                                     4
                                                     4
                                            10k = ln
                                                     3

                                                   1     4
                                               k =    ln            ← k is a positive number
                                                   10    3

                               The function y(t) can now be determined.

                                                                     4
                                                                  1  ln )t
                                                    y(t) = 100e −( 10  3
                                                                 t  ln  4
                                                        = 100e −  10  3
                                                        = 100(e ln  4 3 ) −  10 t
                                                                     t
                                                                   −
                                                                4    10
                                                        = 100
                                                                3
                               To solve the problem, let t = 20.

                                                                  4
                                                                     −2
                                                    y(20) = 100
                                                                  3

                                                                     2
                                                                  3
                                                          = 100
                                                                  4
                                                                  9
                                                          = 100 ·
                                                                  16

                                                          = 56.25 mg




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