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                                              2

                                6. Let f (x) = x . The slope of the tangent line at (2, 4) is m = f (2).
                                                            f (x) = x 2

                                                            f (x) = 2x
                                                            f (2) = 4

                                   The equation of the tangent line can be constructed using the
                                   standard equation for a line:

                                                        y − y 1 = m(x − x 1 )
                                                        y − 4 = 4(x − 2)

                                                        y − 4 = 4x − 8

                                                            y = 4x − 4
                                   Once we sketch the curve and the tangent line, it becomes clear
                                   that horizontal rectangles are best to use.

                                       6 6


                                       4 4                                   (2,4)



                                       2 2
                                                     (x,y)
                                                       1        (x,y)
                                                                 2
                                                          1 1              2 2

                                      − 2
                                      −2
                                                                                        √
                                                                           2
                                   Solving for x in terms of y, the equation y = x becomes x =  y
                                                              y + 4
                                   and y = 4x − 4 becomes x =      .
                                                               4
                                                            4
                                                    A =    (x 2 − x 1 ) dy
                                                          0

                                                           4

                                                             y + 4   √
                                                      =            −   y dy
                                                          0    4
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