Page 23 - How To Solve Word Problems In Calculus
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EXAMPLE 7
                               A 1-mile racetrack has two semicircular ends connected by
                               straight lines. Express the area enclosed by the track as a func-
                               tion of its semicircular radius. Determine its domain.

                                   Solution
                                   Step1
                                                             x

                                            r                                   r



                                            r                                   r

                                                             x
                                   Step2
                                   The enclosed area consists of a rectangle whose dimen-
                               sions are x and 2r and two semicircles of radius r whose com-
                                               2
                               bined area is πr .
                                                       A = 2rx + πr 2

                                   Step3
                                   The perimeter of the figure is the length of the two
                               straight sides added to the lengths of the two semicircular arcs.
                               Thus

                                   2x + 2πr = 1                     Each semicircular arc has length
                                                                    πr. Together, they form a com-
                                   2x = 1 − 2πr                     plete circle whose circumference
                                        1 − 2πr                     is 2πr.
                                   x =
                                           2
                               We substitute into the equation obtained in step 2.


                                                           1 − 2πr
                                                 A(r) = 2r           + πr 2
                                                               2
                                                               2
                                                     = r − 2πr + πr  2
                                                     = r − πr 2

                               Since r cannot be negative, r ≥ 0. The perimeter of the track

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