Page 27 - How To Solve Word Problems In Calculus
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Substituting into the result of step 2,

                                                                     50
                                                            2
                                                   S(x) = 4x + 6x
                                                                    x 2
                                                                300
                                                            2
                                                   S(x) = 4x +
                                                                  x
                               EXAMPLE 9
                               A cylindrical container with a circular base has a surface area
                                      2
                               of 64 ft . Express its volume as a function of its radius.
                                   Solution
                                   Step1

                                                                r





                                                                     h







                                   Step2
                                                                2
                                                         V = πr h

                                   Step3
                                                                            2
                                   The surface area of the cylinder is 64 ft . We solve for h
                               in terms of r.

                                                            2
                                                 2πrh + 2πr = 64
                                                        2πrh = 64 − 2πr  2

                                                                64 − 2πr  2
                                                            h =
                                                                   2πr
                                                                32 − πr  2
                                                            h =
                                                                   πr

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