Page 82 - How To Solve Word Problems In Calculus
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10 seconds after the rocket is launched, y = 10 × 500 = 5000 ft.
2
2
z = 5000 + 2000 2
= 25,000,000 + 4,000,000
= 29,000,000
√
z = 1000 29
Substituting,
√ dz
1000 29 = 5000(500)
dt
√ dz
1000 29 = 2,500,000
dt
dz 2500
= √
dt 29
The distance between the rocket and the radar station is increasing
√
at the rate of 2500/ 29 (approximately 464.2) ft/sec.
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