Page 211 - Industrial Power Engineering and Applications Handbook
P. 211

Special-purpose motors  711 91

























                                                                           Coupling speed
                               Figure 7.22  Accelerating torque with  the use of fluid coupling


          engaged with  load, up to Nr, Tr2 z  1  6ST,   which will now be possible with a standard squirrel cage
                                                      motor.  The  motor starting torque requirement  can  also
          (b) calculating average ordinate\ at points  I  to 6
                                                      be relaxed with the use of flexible couplings. if this can
          =  i[XO + 135 + 185 + 215 + 215 +;(215  + 1001   economize on the cost of  the motor.
          = 165%
                                                      Checking the suitability  of  a slip-ring motor
          Lo'id  aberage torque E 0.68Tr
                                                      With the  same pull-out torque as above,  if  we  select a
          ..       TCi2 = 1.65T, - 0.68T,             slip-ring  motor  and  arrange  the  starter  to  develop  dn
                      = 0.97Tr =   450 x 974 x 0.97   averdge pick-up torque of 200%, the avdilable accelerating
                                                      torque will  be (200 - 68) = 132%
                                    980
                      = 433.33 mkg                        450 x 974   ,.32
                                                      i.e.   980
           and   GD;  = GD<4 + GD:  + GD?
                                                                                   1866 x 980
                      = 200 + 200 + 1666              or  590 mkg and starting time 1,  =   375 x 590
                      = 2066 kgm'                     or  8.26 seconds.
                   N,? = 980 - 800                    Assuming a safe start time of8.26 x 1. 15. i.e. 9.5 seconds,
                                                      a motor with a safe hot stall time of 30 seconds will be
                      = 180 r.p.m.
                                                      adequate to withstand three consecutive hot starts. since
           ...  I,?  from 0.8Nr to N, =   2066 x  180   3 x 9.5 < 30 seconds.
                               375 x 433.83
           (The actual speed will be slightly less due to coupling   Nore  In a slip-ring motor I,,  is much less compared to a squirrel
           slip)                                      cage motor, say 200-300% I,.  and therefore a hot thermal with\tand
                                                      time of only 6 to 9 \econds ~hould be quite safe for such a duty. e.?.
                                = 2.28 seconds
                                                      Heating,  H  = If,. K  t,   lr: . R  t2
           :.   Total  accelerating time = 2.01 + 2.28
                                = 4.29 seconds
           With  permissible tolerance = 1. 15 x 4.29
                                                      Since the thermal  withstand  time refers  to locked  rotor conditions
                                = 4.93 seconds        and normally  corresponds to 600 to 700% I,.
                                                      :.   at 300% I,,.  the equivalent thermal withstand time, considering
         For three consecutive starts, the motor must possess a   the hot thermal  withstand  time at 600% starting current as 8
       minimum thermal  withstand time of about 14.8 seconds   wconds will be
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