Page 230 - Industrial Power Engineering and Applications Handbook
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Transmission of  load and suitability of bearings 8/209

                                                        with an additional power-transmitting capacity for a speed
                                                        ratio of  1.19 = 1.74 kwlbelt.
                                                        :.   Total load-transmitting capacity = 25.62 kWlbelt
                                                        Determine correction factors
                                                         (i)  For the arc of contact shown in Table 8.7, which is
                                                            the same for all manufacturers. Corresponding to an
                                                            arc of contact of  - D-   on the smaller pulley
                                                                          C
                                                            i.e. for   475-400  or  0.077
                                                                   977.40
                                                            The correction factor is not less than 0.99.
                                                         (ii)  Determine the belt pitch length correction factor form
        Arc of                                              (Table 8.6) which is same for all manufacturers.
                                                            Corresponding to L = 3330 mm for the belt of section
                                                            D, it is 0.87.
                                                        Determine the  number  of  belts for  the total  load to  be
                                                        transmitted.
                                                        Corrected power capacity of each belt of section
                                                                            D = 25.62 x 0.99 x 0.87
                                                                             = 22.06 kW
       C    .
                                                                                143
                                                         :.  Number of belts required  = -
                                                                               22.06
                                                                             = 6.48
                                                        or 7 belts
                                                        Counter-check the selection for the speed of the smaller
                                                        pulley.
                                                        Speed = a. d . N, . mmlmin
                                                        where  N, = speed of the faster shaft = 980 r.p.m.
            \   I
            \   I                                             d = pitch dia. of the faster (smaller) pulley
             ?Angle   of belt
             \\  I/                                             = 400 mm.
              \I
          Cross-section                                  :.  Speed of faster pulley  =  n x 400 x 980
           of  a V-belt                                                       60  x 1000
                                                                           = 20.51 mls
         Figure 8.12  Determining the belt details in a V-belt drive
                                                        which is less than 30 rnls, hence acceptable.  Had it not
                                                        been so, advice from the manufacturer on the selection of
                                                        belts would have been necessary.
                                                        Thus the specification of the belts and the pulleys will be
                                                          Belts
                                                          cross-section  - D
                (475 - 400)’
         and  6=                                          pitch length L  - 3330 mm
                    8                                     Number of belts - 7
                = 703.12
                                                        Note  To  avoid uneven distribution  of  load on the belts
         :.   C = 489.06 + J489.06* - 703.12            when more than one belt is used the pitch length of the
                                                        belts must be identical, subject to permissible tolerances.
              = 489.06 + 488.34                         For this purpose,  it is advisable  to use all belts of  one
                                                        make only. As standard practice all belts are marked on
              = 977.40 mm, which is acceptable          their surfaces with their length and permissible tolerance
                                                        for easy identification.
       6  Determine the  power rating  per belt  from  the technical
         data  provided by the  manufacturer. This  will  vary  from   Pulleys
         one manufacturer to another, depending upon the quality   (a) Smaller pulley on motor shaft
         of rubber used. We have considered this data, as shown   Pitch dia. = 400 mm
         in Table 8.4, of a leading manufacturer.          Number of grooves suitable for belts of section D = 7
         Corresponding to 1000 r.p.m.  and d = 400 mm.   (b) Larger pulley on the compressor shaft
                                                           Pitch dia. = 475 mm
         Power rating of  belt having section  D = 23.88 kWlbelt,   Number of grooves suitable for belts of section D = 7
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