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58                                                  CHAPTER 4 PHYSICAL FUNDAMENTALS

                     The form of Eq. (4.56) depends on the chosen balance border. The border
                  can be chosen arbitrarily. When the balance space is chosen according to the
                  balance border 2, the energy equation is





                  Using the values corresponding to the states 1' and 2', hi is the resistance
                  height between V and 2', and p r and p 2> are determined by the pressure loss
                  and initial pressure. Other quantities are determined correspondingly. It is
                  worth noting that there are no outflow losses in this case. Generally, it is wise
                  to use energy balances in calculations.
                     The above is valid for a liquid flow, when the effect of compressibility
                  can be ignored when calculating gas flows with small pressure differences.
                  For instance, in ventilating duct work, air is not compressed, so the density
                  is considered as constant. In HVAC technology a unit of pressure fre-
                  quently used for convenience is a water column millimeter, 1 mm
                  H 2 O«10Pa.

                  4.1.5.5 Pressure Loss in Gas and Steam Pipes
                     When the gas compressibility no longer can be bypassed, the pressure loss
                  equation is written in a differential form





                  where dl is the differential pipe length and D is the diameter.
                     On the basis that pv m A = q m or v m= q m /pA,




                  When both sides of the equation are multiplied by p we have





                  For an ideal gas,



                  or when the gas follows the formula pv = h* /L,, where £ is the process factor
                  and h* = h -h Q, the deviation from the enthalpy of the reference state, Eq.
                  (4.60), can easily be integrated, giving




                  where p/p = constant.
                     If the pressures and densities are known we can solve for either q m or D
                  from this equation.
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